/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 A random sample of 10 houses in ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A random sample of 10 houses in a particular area, each of which is heated with natural gas, is selected, and the amount of gas (in therms) used during the month of January is determined for each house. The resulting observations are as follows: \(\begin{array}{llllllllll}103 & 156 & 118 & 89 & 125 & 147 & 122 & 109 & 138 & 99\end{array}\) a. Let \(\mu_{j}\) denote the average gas usage during January by all houses in this area. Compute a point estimate of \(\mu_{J}\) b. Suppose that 10,000 houses in this area use natural gas for heating. Let \(\tau\) denote the total amount of gas used by all of these houses during January. Estimate \(\tau\) using the given data. What statistic did you use in computing your estimate? c. Use the given data to estimate \(\pi\), the proportion of all houses that used at least 100 therms. d. Give a point estimate of the population median usage based on the given sample. Which statistic did you use?

Short Answer

Expert verified
a. The point estimate of \(\mu_{J}\) is the mean of the data, b. The estimate of \(\tau\) is 12060 therms, c. The estimate of \(\pi\) for houses with at least 100 therm usage is 0.9, d. The point estimate for median usage is 120.5 therms.

Step by step solution

01

Compute a point estimate of \(\mu_{J}\)

Begin by calculating the mean (average) of the given data set. Sum up all the observations and divide this by the number of observations. To obtain the point estimate for \(\mu_{J}\), it is simply equal to the calculated mean.
02

Estimate \(\tau\)

Based on the assumption in the exercise, the population is the set of all houses (10,000) in the area. To estimate \(\tau\), the total amount of gas used by all these houses, multiply the calculated mean by the population size.
03

Estimate \(\pi\)

To estimate \(\pi\), the proportion of all houses that used at least 100 therms, count the number of houses that used 100 or more therms in the sample. Divide this count by the total number of houses in the sample.
04

Compute point estimate of the median usage

The median is the middle value when data points are arranged in ascending order. For this data set, there are 10 points. Therefore the median is the average of the 5th and 6th observations in the ordered list.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Estimation
Estimating the mean is one of the fundamental tasks in statistics. It gives us a point estimate of the average value in a data set. To find the mean of a sample, you need to sum up all the observed values and then divide the total by the number of observations. For example, with our data on gas usage:
  • Add up all the therm values: 103 + 156 + 118 + 89 + 125 + 147 + 122 + 109 + 138 + 99.
  • The sum is 1206.
  • Now divide this total by the number of houses, which is 10.
This gives us a mean of 120.6 therms. This mean acts as a point estimate for \(\mu_{J}\), the average gas usage for all houses in the area. It's easy to see that the mean provides a useful summary of the data, bridging the observed sample to the larger population.
Proportion Calculation
Calculating a proportion helps us understand the relative size of a subset within a larger group. In the exercise, we are interested in the proportion of houses that used at least 100 therms of gas. To calculate this, we:
  • Count how many houses used 100 or more therms. In our data, the counts are 9 (103, 156, 118, 125, 147, 122, 109, 138, 99).
  • There are 10 total observations.
  • Divide the count of qualifying houses (9) by the total number of houses (10).
Thus, the proportion \(\pi\) is 0.9 or 90%. Proportion calculation is particularly useful in scenarios where we want to make predictions or infer trends about a population, based on sample data. It helps in distinguishing how frequently a particular trait or characteristic appears within the data set.
Median Estimation
The median gives a robust measure of central tendency and provides valuable insight, especially for skewed distributions. To estimate the median, arrange your data in ascending order:
  • Ordered values: 89, 99, 103, 109, 118, 122, 125, 138, 147, 156.
  • For ten pieces of data, the median will be the average of the 5th and 6th values.
  • These values are 118 and 122.
  • Average them to get the median: (118 + 122)/2 = 120.
This value, 120, is the point estimate of the population median. Median is less affected by extreme values (outliers) and thereby can reveal a more representative center of the dataset than the mean in certain conditions.
Sample Data Analysis
Analyzing a sample involves extracting key statistics to make informed estimates about a larger population. In our example, we examine a sample of gas usage data to predict broader trends and figures. Here's what we did:
  • Calculated the mean to represent the average gas usage.
  • Estimated the total gas usage for the entire population by scaling the sample mean.
  • Determined the proportion of houses exceeding a specific threshold.
  • Appraised the median to understand the central usage figure, unaffected by outliers.
Effective sample data analysis enables us to make educated guesses about the population from which the sample is drawn, improving our decision-making and strategic planning abilities. By leveraging mean, proportion, and median calculations, we succinctly interpret raw data and provide a snapshot into potential real-world scenarios.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Recent high-profile legal cases have many people reevaluating the jury system. Many believe that juries in criminal trials should be able to convict on less than a unanimous vote. To assess support for this idea, investigators asked each individual in a random sample of Californians whether they favored allowing conviction by a 10-2 verdict in criminal cases not involving the death penalty. The Associated Press (San Luis Obispo TelegramTribune, September 13,1995 ) reported that \(71 \%\) supported the \(10-2\) verdict. Suppose that the sample size for this survey was \(n=900\). Compute and interpret a \(99 \%\) confidence interval for the proportion of Californians who favor the \(10-2\) verdict.

The article "Viewers Speak Out Against Reality TV" (Associated Press, September 12,2005\()\) included the following statement: "Few people believe there's much reality in reality TV: a total of 82 percent said the shows are either 'totally made up' or 'mostly distorted'." This statement was based on a survey of 1002 randomly selected adults. Compute and interpret a bound on the error of estimation for the reported percentage.

The article "National Geographic, the Doomsday Machine," which appeared in the March 1976 issue of the Journal of Irreproducible Results (yes, there really is a journal by that name-it's a spoof of technical journals!) predicted dire consequences resulting from a nationwide buildup of National Geographic magazines. The author's predictions are based on the observation that the number of subscriptions for National Geographic is on the rise and that no one ever throws away a copy of National Geographic. A key to the analysis presented in the article is the weight of an issue of the magazine. Suppose that you were assigned the task of estimating the average weight of an issue of National Geographic. How many issues should you sample to estimate the average weight to within 0.1 oz with \(95 \%\) confidence? Assume that \(\sigma\) is known to be 1 oz.

would result in a wider large-sample cont?dence interval for \(\pi\) : a. \(90 \%\) confidence level or \(95 \%\) confidence level b. \(n=100\) or \(n=400\)

An Associated Press article on potential violent behavior reported the results of a survey of 750 workers who were employed full time (San Luis Obispo Tribune, September 7,1999 ). Of those surveyed, 125 indicated that they were so angered by a coworker during the past year that they felt like hitting the coworker (but didn't). Assuming that it is reasonable to regard this sample of 750 as a random sample from the population of full-time workers. use this information to construct and interpret a \(90 \%\) confidence interval estimate of \(\pi\), the true proportion of fulltime workers so angered in the last year that they wanted to hit a colleague.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.