/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 P-value Indicate whether each of... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

P-value Indicate whether each of the following P-values gives strong evidence or not especially strong evidence against the null hypothesis. a. 0.38 b. 0.001

Short Answer

Expert verified
P-value 0.38 is not strong evidence against the null hypothesis; P-value 0.001 is strong evidence against the null hypothesis.

Step by step solution

01

Understanding the P-value

The P-value is a measure used in statistical hypothesis testing to determine the significance of the results. It quantifies the probability of observing the data, or something more extreme, assuming the null hypothesis is true. A smaller P-value indicates stronger evidence against the null hypothesis.
02

Defining the Threshold for Strong Evidence

Typically, a common threshold for considering evidence as strong in hypothesis testing is a P-value less than 0.05. If the P-value is less than this threshold, there is generally strong evidence against the null hypothesis; if it is larger, the evidence is not considered strong.
03

Evaluating P-value for 0.38

Compare the P-value of 0.38 to the threshold of 0.05. Since 0.38 is much greater than 0.05, it is not considered to provide strong evidence against the null hypothesis.
04

Evaluating P-value for 0.001

Compare the P-value of 0.001 to the threshold of 0.05. Since 0.001 is much smaller than 0.05, it provides strong evidence against the null hypothesis.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Hypothesis Testing
Statistical hypothesis testing is a powerful method for making decisions about a population based on sample data. In a statistical test, you start with two competing hypotheses: the null hypothesis and the alternative hypothesis. The goal is to determine which hypothesis the sample data supports. Statistical testing helps us understand if the observed data can happen by chance alone or if it's actually indicative of a meaningful pattern.

Here's how it generally works:
  • You collect data from a sample.
  • You choose a statistical test suitable for your data and hypotheses.
  • You calculate the test statistic and p-value.
  • You compare the p-value against a chosen significance threshold to make a decision.
Statistical hypothesis tests are essential tools in fields like medicine, economics, and engineering, enabling experts to make data-driven decisions and validate theories.
Null Hypothesis
The null hypothesis, often denoted as \( H_0 \), is a primary concept in hypothesis testing. When you form a null hypothesis, you're suggesting that any observed effect in your data is due to random chance and there is no true underlying effect. In simpler terms, the null hypothesis assumes that nothing special is happening.

For example, if you're testing a new drug, your null hypothesis might state that "the new drug has no effect." By starting with this assumption, you test whether your data provides enough evidence to conclude something different.
Here are some key points about the null hypothesis:
  • It's generally a statement of no effect or no difference.
  • The null hypothesis is tested directly, and researchers look for evidence that contradicts it.
  • Rejecting the null hypothesis suggests there is an effect or difference, while failing to reject it suggests no significant change or effect.
The null hypothesis is a crucial building block in statistical testing because it sets the stage for all testing activities.
Significance Threshold
In hypothesis testing, the significance threshold, often represented as \( \alpha \), is a benchmark set by researchers to decide when to reject the null hypothesis. It represents the probability of rejecting the null hypothesis when it is actually true – essentially, it's the risk you are willing to take for a false positive, known as a Type I error.

Common significance thresholds include:
  • 0.05: There's a 5% chance of incorrectly rejecting the null hypothesis.
  • 0.01: More stringent, with a 1% chance.
  • 0.10: Less stringent, accepted in some exploratory studies.
When you calculate a p-value and it is less than the chosen significance threshold, you have evidence to reject the null hypothesis. This doesn't "prove" the alternative hypothesis, but it strongly suggests that the observed data isn't due to random chance alone.
The significance threshold is a key decision point in hypothesis testing, guiding whether we accept or question the null hypothesis based on our data's p-value.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Effect of \(n\) Example 11 analyzed political conservatism and liberalism in the United States. Suppose that the sample mean of 4.11 and sample standard deviation of 1.43 were from a sample size of only 25 , rather than 1933 . a. Find the test statistic. b. Find the P-value for testing \(\mathrm{H}_{0}: \mu=4.0\) against \(\mathrm{H}_{a}: \mu \neq 4.0 .\) Interpret. c. Show that a \(95 \%\) confidence interval for \(\mu\) is (3.5,4.7) . d. Together with the results of Example \(11,\) explain what this illustrates about the effect of sample size on (i) the size of the P-value (for a given mean and standard deviation) and (ii) the width of the confidence interval.

Decision errors in medical diagnostic testing Consider medical diagnostic testing, such as using a mammogram to detect if a woman may have breast cancer. Define the null hypothesis of no effect as the patient does not have the disease. Define rejecting \(\mathrm{H}_{0}\) as concluding that the patient has the disease. See the table for a summary of the possible outcomes: $$ \begin{array}{lll} \hline & \text { Medical Diagnostic Testing } & \\ \hline & {\text { Medical Diagnosis }} \\ \hline \text { Disease } & \text { Negative } & \text { Positive } \\ \hline \text { No }\left(\mathrm{H}_{0}\right) & \text { Correct } & \text { Type I error } \\ \text { Yes }\left(\mathrm{H}_{a}\right) & \text { Type II error } & \text { Correct } \\ \hline \end{array} $$ a. When a radiologist interprets a mammogram, explain why a Type I error is a false positive, predicting that a woman has breast cancer when actually she does not. b. A Type II error is a false negative. What does this mean, and what is the consequence of such an error to the woman? c. A radiologist wants to decrease the chance of telling a woman that she may have breast cancer when actually she does not. Consequently, a positive test result will be reported only when there is extremely strong evidence that breast cancer is present. What is the disadvantage of this approach?

Practice mechanics of a \(t\) test A study has a random sample of 20 subjects. The test statistic for testing \(\mathrm{H}_{0}: \mu=100\) is \(t=2.40\). Find the approximate P-value for the alternative, (a) \(\mathrm{H}_{a}: \mu \neq 100,\) (b) \(\mathrm{H}_{a}: \mu>100,\) and (c) \(\mathrm{H}_{a} ; \mu<100\).

Test and CI Results of \(99 \%\) confidence intervals are consistent with results of two-sided tests with which significance level? Explain the connection.

Men at work When the 636 male workers in the 2008 GSS were asked how many hours they worked in the previous week, the mean was 45.5 with a standard deviation of 15.16 . Does this suggest that the population mean work week for men exceeds 40 hours? Answer by: a. Identifying the relevant variable and parameter. b. Stating null and alternative hypotheses. c. Reporting and interpreting the P-value for the test statistic value of \(t=9.15\). d. Explaining how to make a decision for the significance level of 0.01

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.