/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 Examples of hypotheses Give an e... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Examples of hypotheses Give an example of a null hypothesis and an alternative hypothesis about a (a) population proportion and (b) population mean.

Short Answer

Expert verified
For population proportion: \( H_0: p = 0.60 \), \( H_a: p \neq 0.60 \). For population mean: \( H_0: \mu = 95 \), \( H_a: \mu \neq 95 \).

Step by step solution

01

Understanding Hypotheses

Before providing examples, it's important to understand what a null hypothesis and an alternative hypothesis are. The null hypothesis (denoted as \( H_0 \)) is a statement of no effect or no difference, and it is what we aim to test. The alternative hypothesis (denoted as \( H_a \)) is the statement we want to provide evidence for, indicating some effect or difference.
02

Example of a Null and Alternative Hypothesis on Population Proportion

For a population proportion scenario, consider a manufacturer claiming that 60% of its product is free of defects. The null hypothesis would be \( H_0: p = 0.60 \), stating that the population proportion is 60%. The alternative hypothesis could be \( H_a: p eq 0.60 \), \( H_a: p < 0.60 \), or \( H_a: p > 0.60 \), depending on whether we suspect the proportion is not 60%, less than 60%, or more than 60%, respectively.
03

Example of a Null and Alternative Hypothesis on Population Mean

Consider a situation where a coffee company claims the average caffeine content of its coffee is 95 mg per cup. The null hypothesis would be \( H_0: \mu = 95 \), stating that the average caffeine content is 95 mg. The alternative hypothesis could be \( H_a: \mu eq 95 \), \( H_a: \mu < 95 \), or \( H_a: \mu > 95 \), depending on whether the suspicion is that the mean is not 95 mg, less than 95 mg, or more than 95 mg.
04

Choosing the Right Test Direction

The choice of alternative hypothesis direction (\( eq, <, > \)) is based on the original claim or suspected deviation from the null hypothesis. If no direction is specified, \( eq \) is used, indicating a two-tailed test.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
Null hypothesis plays a crucial role in statistics, especially in the field of hypothesis testing. When we talk about the null hypothesis, denoted as \( H_0 \), it represents a statement that suggests no effect or no significant difference within a particular context. This is essentially the default position that indicates that there is nothing unusual happening. The null hypothesis is akin to the 'status quo'.
When you conduct a hypothesis test, the primary goal is to challenge this initial assumption (i.e., the null hypothesis) to see if there is substantial evidence to believe otherwise. For instance, if a claim states that 50% of voters support a candidate, the null hypothesis would be that exactly 50% support exists (\( H_0: p = 0.50 \)).
It's important to note that the null hypothesis carries an equal likelihood for both the acceptance and rejection of its stance; hence, any conclusions drawn are derived from statistical testing rather than mere assumptions.
Alternative Hypothesis
The alternative hypothesis, represented as \( H_a \), is the statement that suggests a potential effect or difference from what the null hypothesis states. This hypothesis takes center stage when the null hypothesis is found inadequate or false. The alternative hypothesis essentially reflects what one expects to prove or show evidence for during the hypothesis testing.
Different scenarios can involve various forms of alternative hypotheses such as:
  • Two-tailed test: \( H_a: \text{parameter} eq \text{value} \)
  • Left-tailed test: \( H_a: \text{parameter} < \text{value} \)
  • Right-tailed test: \( H_a: \text{parameter} > \text{value} \)
By correctly defining the alternative hypothesis, one ensures that the test's direction aligns with the expectations or suspicions about the population being studied, such as noting whether a proportion or mean could be more, less, or substantially different from the claimed value.
Population Proportion
Population proportion is a measure often used to understand or compare subsets of data. It is denoted by \( p \) and describes the fraction of the population that possesses a certain characteristic. Knowing the population proportion allows statisticians to make informed decisions about how typical or atypical results from sample data might be.
For example, consider a medical trial aiming to determine the effectiveness of a new drug. If a company claims that 80% of patients experience improvement, the null hypothesis would be \( H_0: p = 0.80 \). An investigator may have a reason to believe differently, thus forming an alternative hypothesis, such as \( H_a: p > 0.80 \) or \( H_a: p < 0.80 \).
This method of using population proportion is fundamental in identifying if observed sample data falls within the expected range of outcomes or if it suggests a significant divergence worthy of further exploration.
Population Mean
The population mean, symbolized as \( \mu \), represents the average value of a specific set of data points within a given population. In statistics, determining the population mean is central to validate claims about standard practices or benchmarks.
Consider as an example, a quality control inspector analyzing the weight of cereal boxes in a factory. If the company claims the average weight is 500 grams, the null hypothesis would be \( H_0: \mu = 500 \). Any deviations that analysts suspect would form the basis of the alternative hypothesis, such as \( H_a: \mu < 500 \) or \( H_a: \mu > 500 \).
Understanding the concept of population mean assists analysts in evaluating whether sample data concurs with the asserted population norm or whether it indicates a potential issue or variation from the expectation.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Practice mechanics of a \(t\) test A study has a random sample of 20 subjects. The test statistic for testing \(\mathrm{H}_{0}: \mu=100\) is \(t=2.40\). Find the approximate P-value for the alternative, (a) \(\mathrm{H}_{a}: \mu \neq 100,\) (b) \(\mathrm{H}_{a}: \mu>100,\) and (c) \(\mathrm{H}_{a} ; \mu<100\).

Dr. Dog In the experiment in Example \(4,\) we got a P-value \(=0.000\) for testing \(\mathrm{H}_{0}=\mathrm{p}=1 / 7\) about dogs ability to diagnose urine from bladder cancer patients. a. For the significance level \(0.05,\) what decision would you make? b. If you made an error in part a, what type of error was it? Explain what the error means in context of the Dr. Dog experiment.

Error probability A significance test about a proportion is conducted using a significance level of \(0.05 .\) The test statistic equals \(2.58 .\) The P-value is 0.01 a. If \(\mathrm{H}_{0}\) were true, for what probability of a Type I error was the test designed? b. If this test resulted in a decision error, what type of error was it?

Alabama GPA Suppose the mean GPA of all students graduating from the University of Alabama in 1985 was 3.05. The registrar plans to look at records of students graduating in 2011 to see if mean GPA has changed. Define notation and state the null and alternative hypotheses for this investigation.

Men at work When the 636 male workers in the 2008 GSS were asked how many hours they worked in the previous week, the mean was 45.5 with a standard deviation of 15.16 . Does this suggest that the population mean work week for men exceeds 40 hours? Answer by: a. Identifying the relevant variable and parameter. b. Stating null and alternative hypotheses. c. Reporting and interpreting the P-value for the test statistic value of \(t=9.15\). d. Explaining how to make a decision for the significance level of 0.01

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.