/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 42 Dr. Dog In the experiment in Exa... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Dr. Dog In the experiment in Example \(4,\) we got a P-value \(=0.000\) for testing \(\mathrm{H}_{0}=\mathrm{p}=1 / 7\) about dogs ability to diagnose urine from bladder cancer patients. a. For the significance level \(0.05,\) what decision would you make? b. If you made an error in part a, what type of error was it? Explain what the error means in context of the Dr. Dog experiment.

Short Answer

Expert verified
a. Reject \(H_0\) at significance level 0.05. b. Type I error: concluding difference in ability when there is none.

Step by step solution

01

Understand Hypothesis Tests

In hypothesis testing, we are testing the null hypothesis (\(H_0\)) against an alternative hypothesis (\(H_a\)). For this experiment, the null hypothesis is \(H_0: p = \frac{1}{7}\), meaning the probability of the dog's correct diagnosis is \(\frac{1}{7}\).
02

Review Significance Level

The significance level, \(\alpha\), is a threshold for deciding when to reject the null hypothesis. Here, \(\alpha = 0.05\). If the P-value is less than \(\alpha\), we reject \(H_0\). If the P-value is greater than \(\alpha\), we fail to reject \(H_0\).
03

Compare P-value and Significance Level

The given P-value from the experiment is 0.000. Since this is less than the significance level of 0.05, we reject the null hypothesis \(H_0: p = \frac{1}{7}\).
04

Make a Decision

Given the comparison in Step 3, we reject \(H_0\) and conclude that there is sufficient evidence to suggest the dog's ability is different from \(\frac{1}{7}\).
05

Identify Potential Errors

In hypothesis testing, if we reject \(H_0\) when it is actually true, this is a Type I error. A Type I error occurs when we conclude there is an effect or difference when in fact none exists.
06

Explain Error in Context

A Type I error in the context of the Dr. Dog experiment means we incorrectly concluded that the dog has a different diagnostic ability than \(\frac{1}{7}\), when in reality, it doesn't. This could suggest the dog has an ability to diagnose correctly that's no better or worse than \(\frac{1}{7}\), but we mistakenly thought it did.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Type I Error
In hypothesis testing, we assess two possible decisions: rejecting or failing to reject the null hypothesis (\(H_0\)). Whenever we decide to reject \(H_0\) but it was actually true, this is what we call a Type I Error. The implications of a Type I Error are significant, as they lead us to believe that an effect or difference exists when it truly doesn't.

Consider the Dr. Dog experiment. Here, a Type I Error would mean mistakenly concluding that the dog has a superior ability to diagnose correctly, different from \(\frac{1}{7}\), when in reality, that isn't the case. Such an incorrect decision could lead to incorrect applications or inefficient strategies based on false premises. In practical terms, you may spend resources and time pursuing a path that doesn't yield the expected results.

While no testing process is free from error, understanding the implications of a Type I Error ensures that one can interpret the results from hypotheses tests more accurately and make informed decisions.
P-value
The P-value is a critical component in hypothesis testing as it helps us determine the strength of our results. It represents the probability of obtaining a test result at least as extreme as the observed one, assuming that the null hypothesis \( \mathrm{H}_{0} \) is true.

A P-value can help us decide on whether to reject or fail to reject \( \mathrm{H}_{0} \). The general rule is:
  • If the P-value is less than the significance level \(\alpha\), reject \( \mathrm{H}_{0} \).
  • If it is greater than \(\alpha\), fail to reject \( \mathrm{H}_{0} \).
In the Dr. Dog experiment, the P-value was \(0.000\). Since \(0.000\) is less than the significance level of \(0.05\), this indicates very strong evidence against the null hypothesis \( \mathrm{H}_{0} \), leading to its rejection. The smaller the P-value, the stronger the evidence to reject \( \mathrm{H}_{0} \), highlighting that the dog's diagnostic ability might not be \( \frac{1}{7} \) as originally hypothesized. The P-value essentially quantifies the evidence in the data regarding the null hypothesis.
Significance Level
The significance level, denoted by \(\alpha\), is a pre-determined threshold used in hypothesis testing to decide whether to reject \( \mathrm{H}_{0} \). It marks the boundary for considering a result statistically significant. Common levels used are \(0.05\), \(0.01\), and \(0.10\).

In our example, the significance level of \(0.05\) was chosen. This means that there is a 5% risk of concluding that a difference exists when there is none—a maximum frequency for committing a Type I Error.
By comparing the P-value to \(\alpha\), we decide if the evidence is strong enough to reject \( \mathrm{H}_{0} \). When the P-value is less than \(\alpha\), we reject \( \mathrm{H}_{0} \), suggesting the results are statistically significant. Conversely, if the P-value is greater, we fail to reject \( \mathrm{H}_{0} \), accepting the results as not significant.

Choosing the right significance level is crucial. Lower \(\alpha\) levels indicate stricter criteria for evidence, reducing the chance of Type I Error but making it harder to reject \( \mathrm{H}_{0} \). In the Dr. Dog study, using 0.05 meant that only strong evidence against the null hypothesis would lead to its rejection, as seen when the P-value was 0.000.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Testing a headache remedy Studies that compare treatments for chronic medical conditions such as headaches can use the same subjects for each treatment. This type of study is commonly referred to as a crossover design. With a crossover design, each person crosses over from using one treatment to another during the study. One such study considered a drug (a pill called Sumatriptan) for treating migraine headaches in a convenience sample of children. The study observed each of 30 children at two times when he or she had a migraine headache. The child received the drug at one time and a placebo at the other time. The order of treatment was randomized and the study was double-blind. For each child, the response was whether the drug or the placebo provided better pain relief. Let \(p\) denote the proportion of children having better pain relief with the drug, in the population of children who suffer periodically from migraine headaches. Can you conclude that \(p>0.50,\) with more than half of the population getting better pain relief with the drug, or that \(p<0.50\), with less than half getting better pain relief with the drug (i.e., the placebo being better)? Of the 30 children, 22 had more pain relief with the drug and 8 had more pain relief with the placebo. a. For testing \(\mathrm{H}_{0}: p=0.50\) against \(\mathrm{H}_{a}: p \neq 0.50\), show that the test statistic \(z=2.56\). b. Show that the P-value is 0.01 . Interpret. c. Check the assumptions needed for this test, and discuss the limitations due to using a convenience sample rather than a random sample.

A person who claims to be psychic says that the probability \(p\) that he can correctly predict the outcome of the roll of a die in another room is greater than \(1 / 6,\) the value that applies with random guessing. If we want to test this claim, we could use the data from an experiment in which he predicts the outcomes for \(n\) rolls of the die. State hypotheses for a significance test, letting the alternative hypothesis reflect the psychic's claim.

Get P-value from \(z\) For a test of \(\mathrm{H}_{0}: p=0.50,\) the \(z\) test statistic equals 1.04 a. Find the P-value for \(\mathrm{H}_{a} \cdot p>0.50\). b. Find the P-value for \(\mathrm{H}_{a}: p \neq 0.50\). c. Find the P-value for \(\mathrm{H}_{c}: p<0.50 .\) (Hint: The P-values for the two possible one-sided tests must sum to \(1 .)\) d. Do any of the P-values in part a, part b, or part c give strong evidence against \(\mathrm{H}_{0}\) ? Explain.

Men at work When the 636 male workers in the 2008 GSS were asked how many hours they worked in the previous week, the mean was 45.5 with a standard deviation of 15.16 . Does this suggest that the population mean work week for men exceeds 40 hours? Answer by: a. Identifying the relevant variable and parameter. b. Stating null and alternative hypotheses. c. Reporting and interpreting the P-value for the test statistic value of \(t=9.15\). d. Explaining how to make a decision for the significance level of 0.01

Low-carbohydrate diet A study plans to have a sample of obese adults follow a proposed low-carbohydrate diet for three months. The diet imposes limited eating of starches (such as bread and pasta) and sweets, but otherwise no limit on calorie intake. Consider the hypothesis, The population mean of the values of weight change \((=\) weight at start of study \(-\) weight at end of study) is a positive number. a. Is this a null or an alternative hypothesis? Explain your reasoning. b. Define a relevant parameter, and express the hypothesis that the diet has no effect in terms of that parameter. Is it a null or alternative hypothesis?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.