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The article 鈥淓ffects of Short-Term Warming on Low and High Latitude Forest Ant Communities鈥 (Ecoshpere, May 2011, Article 62) described an experiment in which observations on various characteristics were made using mini chambers of three different types: (1) cooler (PVC

frames covered with shade cloth), (2) control (PVC frames only), and (3) warmer (PVC frames covered with plastic).One of the article鈥檚 authors kindly supplied the accompanying data on the difference between air and soil temperatures(掳C).

Cooler Control Warmer

1.59 1.92 2.57

1.43 2.00 2.60

1.88 2.19 1.93

1.26 1.12 1.58

1.91 1.78 2.30

1.86 1.84 0.84

1.90 2.45 2.65

1.57 2.03 0.12

1.79 1.52 2.74

1.72 0.53 2.53

2.41 1.90 2.13

2.34 2.86

0.83 2.31

1.34 1.91

1.76

a. Compare measures of center for the three different samples.

b. Calculate, interpret, and compare the standard deviations for the three different samples.

c. Do the fourth spreads for the three samples convey the same message as do the standard deviations about relative variability?

d. Construct a comparative boxplot (which was included in the cited article) and comment on any interesting features.

Short Answer

Expert verified

a.

The sample mean for Warmer is greater than both Cooler and Control.

b.

The standard deviation of the chamber Cooler is 0.40.

The standard deviation of the chamber control is 0.53.

The standard deviation of the chamber warmer is 0.78.

c.

The fourth spread of the cooler chamber is 0.47.

The fourth spread of the control chamber is 0.51.

The fourth spread of the warmer chamber is 0.69.

d. The comparative boxplot is represented as,

Step by step solution

01

Given information

The data for three mini chambers are provided.

02

Computing the measures of center

a.

Let x represents the values of cooler.

Let y represents the values of control.

Let z represents the values of warmer.

The mean values are computed as,

The sample mean of x is computed as,

\(\begin{array}{c}\bar x &=& \frac{{\sum x }}{{{n_x}}}\\ &=& \frac{{1.59 + 1.43 + 1.88 + ... + 1.76}}{{15}}\\ &=& 1.71\end{array}\)

Thus, the sample mean of x is 1.71.

The sample mean of y is computed as,

\(\begin{array}{c}\bar y &=& \frac{{\sum y }}{{{n_y}}}\\ &=& \frac{{1.92 + 2.0 + 2.19 + ... + 1.9}}{{11}}\\ &=& 1.75\end{array}\)

Thus, the sample mean of y is 1.75.

The sample mean of z is computed as,

\(\begin{array}{c}\bar z &=& \frac{{\sum z }}{{{n_z}}}\\ &=& \frac{{2.57 + 2.60 + 1.93 + ... + 1.91}}{{14}}\\ &=& 2.08\end{array}\)

Thus, the sample mean of z is 2.08.

It can be observed that the sample mean for Warmer is greater than both Cooler and Control.

03

Computing the standard deviation

b.

Referring to part a,

The sample mean of x is 1.71.

The sample mean of y is 1.75.

The sample mean of z is 2.08.

The standard deviation is computed as,

For x,

\(\begin{array}{c}{s_x} &=& \sqrt {\frac{{\sum {{{\left( {{x_i} - \bar x} \right)}^2}} }}{{{n_x} - 1}}} \\ &=& \sqrt {\frac{{{{\left( {1.59 - 1.71} \right)}^2} + {{\left( {1.43 - 1.71} \right)}^2} + ... + {{\left( {1.76 - 1.71} \right)}^2}}}{{15 - 1}}} \\ &=& 0.40\end{array}\)

For y,

\(\begin{array}{c}{s_y} &=& \sqrt {\frac{{\sum {{{\left( {{y_i} - \bar y} \right)}^2}} }}{{{n_y} - 1}}} \\ &=& \sqrt {\frac{{{{\left( {1.92 - 1.75} \right)}^2} + {{\left( {2.0 - 1.75} \right)}^2} + ... + {{\left( {1.9 - 1.75} \right)}^2}}}{{11 - 1}}} \\ &=& 0.53\end{array}\)

For z,

\(\begin{array}{c}{s_z} &=& \sqrt {\frac{{\sum {{{\left( {{z_i} - \bar z} \right)}^2}} }}{{{n_z} - 1}}} \\ &=& \sqrt {\frac{{{{\left( {2.57 - 2.08} \right)}^2} + {{\left( {2.6 - 2.08} \right)}^2} + ... + {{\left( {1.91 - 2.08} \right)}^2}}}{{14 - 1}}} \\ &=& 0.78\end{array}\)

It can be observed that the standard deviation of the chamber cooler is less than the standard deviation of the chamber warmer and control.

04

Computing the fourth spread

c.

The fourth spread is computed as,

\({f_s} = {\rm{Upper}}\,{\rm{fourth}} - {\rm{Lower}}\;{\rm{fourth}}\)

where the upper fourth is the median value of the largest half and the lower fourth is the median value of the smallest half.

The number of observations for the cooler chamber is 15 (odd).

The number of observations for the control chamber is 11 (odd).

The number of observations for the warmer chamber is 14 (even).

Arranging the data in ascending order,

Cooler

Control

Warmer

0.83

0.53

0.12

1.26

1.12

0.84

1.34

1.52

1.58

1.43

1.78

1.91

1.57

1.84

1.93

1.59

1.9

2.13

1.72

1.92

2.3

1.76

2

2.31

1.79

2.03

2.53

1.86

2.19

2.57

1.88

2.45

2.6

1.9


2.65

1.91


2.74

2.34


2.86

2.41



For cooler,

\(\begin{array}{l}{n_{smallest}} &=& 7\\{n_{{\rm{largest}}}} &=& 7\end{array}\)

The lower fourth is computed as,

\(\begin{array}{c}\frac{{{n_{smallest}} + 1}}{2} &=& \frac{{7 + 1}}{2}\\ &=& {4^{th}}value\end{array}\)

The 4th value of the smallest half is 1.43.

This implies that the lower fourth is 1.43.

The upper fourth is computed as,

\(\begin{array}{c}\frac{{{n_{{\rm{largest}}}} + 1}}{2} &=& \frac{{7 + 1}}{2}\\ &=& {4^{th}}value\end{array}\)

The 4th value of the largest half is 1.9.

This implies that the upper fourth is 1.9.

The fourth spread for the chamber cooler is computed as,

\(\begin{array}{c}{f_s} &=& {\rm{Upper}}\,{\rm{fourth}} - {\rm{Lower}}\;{\rm{fourth}}\\ &=& 1.9 - 1.43\\ &=& 0.47\end{array}\)

Thus, the fourth spread of cooler chamber is 0.47.

For control,

\(\begin{array}{l}{n_{smallest}} &=& 5\\{n_{{\rm{largest}}}} &=& 5\end{array}\)

The lower fourth is computed as,

\(\begin{array}{c}\frac{{{n_{smallest}} + 1}}{2} &=& \frac{{5 + 1}}{2}\\ &=& {3^{rd}}value\end{array}\)

The 3rd value of the smallest half is 1.52.

This implies that the lower fourth is 1.52.

The upper fourth is computed as,

\(\begin{array}{c}\frac{{{n_{{\rm{largest}}}} + 1}}{2} &=& \frac{{5 + 1}}{2}\\ &=& {3^{rd}}value\end{array}\)

The 3rd value of the largest half is 2.03.

This implies that the upper fourth is 2.03.

The fourth spread for the chamber cooler is computed as,

\(\begin{array}{c}{f_s} &=& {\rm{Upper}}\,{\rm{fourth}} - {\rm{Lower}}\;{\rm{fourth}}\\ &=& 2.03 - 1.52\\ &=& 0.51\end{array}\)

Thus, the fourth spread of control chamber is 0.51.

For warmer,

\(\begin{array}{l}{n_{smallest}} &=& 7\\{n_{{\rm{largest}}}} &=& 7\end{array}\)

The lower fourth is computed as,

\(\begin{array}{c}\frac{{{n_{smallest}} + 1}}{2} &=& \frac{{7 + 1}}{2}\\ &=& {4^{th}}value\end{array}\)

The 4th value of the smallest half is 1.91.

This implies that the lower fourth is 1.91.

The upper fourth is computed as,

\(\begin{array}{c}\frac{{{n_{{\rm{largest}}}} + 1}}{2} &=& \frac{{7 + 1}}{2}\\ &=& {4^{th}}value\end{array}\)

The 4th value of the largest half is 2.6.

This implies that the upper fourth is 2.6.

The fourth spread for the chamber cooler is computed as,

\(\begin{array}{c}{f_s} &=& {\rm{Upper}}\,{\rm{fourth}} - {\rm{Lower}}\;{\rm{fourth}}\\ &=& 2.6 - 1.91\\ &=& 0.69\end{array}\)

Thus, the fourth spread of the warmer chamber is 0.69.

It can be observed that the fourth spread of the chamber cooler is less than the fourth spread of the chamber warmer and control.

05

Construction of a comparative boxplot

Arranging the data in ascending order to compute the value of median,

Cooler

Control

Warmer

0.83

0.53

0.12

1.26

1.12

0.84

1.34

1.52

1.58

1.43

1.78

1.91

1.57

1.84

1.93

1.59

1.9

2.13

1.72

1.92

2.3

1.76

2

2.31

1.79

2.03

2.53

1.86

2.19

2.57

1.88

2.45

2.6

1.9


2.65

1.91


2.74

2.34


2.86

2.41



For Cooler chamber,

For the odd number of observations, the median value is computed as,

\(\begin{array}{c}\tilde x &=& \;{\left( {\frac{{n + 1}}{2}} \right)^{th}}\;ordered\;value\\ &=& \;{\left( {\frac{{15 + 1}}{2}} \right)^{th}}\;ordered\;values\\ &=& \;{\left( 8 \right)^{th}}\;ordered\;values\\ &=& 1.76\end{array}\)

Thus, the median value is 1.76.

For Control chamber,

For the odd number of observations, the median value is computed as,

\(\begin{array}{c}\tilde y &=& \;{\left( {\frac{{n + 1}}{2}} \right)^{th}}\;ordered\;value\\ &=& \;{\left( {\frac{{11 + 1}}{2}} \right)^{th}}\;ordered\;values\\ &=& \;{\left( 6 \right)^{th}}\;ordered\;values\\ &=& 1.9\end{array}\)

Thus, the median value is 1.9.

For Warmer chamber,

For the even number of observations, the median value is computed as,

\(\begin{array}{c}\tilde z &=& average\;of\;{\left( {\frac{n}{2}} \right)^{th}}and\;{\left( {\frac{n}{2} + 1} \right)^{th}}\;ordered\;values\\ &=& average\;of\;{\left( {\frac{{14}}{2}} \right)^{th}}and\;{\left( {\frac{{14}}{2} + 1} \right)^{th}}\;ordered\;values\\ &=& average\;of\;{\left( 7 \right)^{th}}and\;{\left( 8 \right)^{th}}\;ordered\;values\\ &=& \frac{{2.3 + 2.31}}{2}\\ &=& 2.305\end{array}\)

Thus, the median value is 2.305.

Referring to part c,

For Cooler chamber,

The five number summary is,

The lower fourth is 1.43.

The upper fourth is 1.9.

The fourth spread is 0.47.

The smallest observation is 0.83

The largest observation is 2.41.

The median value is 1.76.

For Control chamber,

The five number summary is,

The lower fourth is 1.52.

The upper fourth is 2.03.

The fourth spread is 0.51.

The smallest observation is 0.53

The largest observation is 2.45.

The median value is 1.9.

For Warmer chamber,

The five number summary is,

The lower fourth is 1.91.

The upper fourth is 2.6.

The fourth spread is 0.69.

The smallest observation is 0.12.

The median value is 2.305.

The largest observation is 2.86.

Steps to construct a boxplot are as follows,

1)Compute the values of the five-number summary (smallest value, lower fourth, median, upper fourth, largest value).

2)Construct a line segment from the smallest value to the largest value of the dataset.

3) Construct a rectangular box from the lower fourth to upper fourth and draw a line in the box at the median value.

The boxplot is represented as,

The red boxplot represents the Cooler chamber, blue represents the Control chamber and green represents the Warmer chamber.

The features that can be observed from the above represented boxplot are,

1)There is no outlier present in the cooler chamber whereas there are outliers in other chambers.

2)The distribution of the cooler and control chamber is positively skewed whereas, for the warmer chamber, the distribution is approximately symmetric.

3)The average temperature for the warmer chamber is greater as compared to other two chambers.

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Most popular questions from this chapter

Using a long rod that has length \({\rm{\mu }}\)you are going to lay out a square plot in which the length of each side is \({\rm{\mu }}\).Thus the area of the plot will be \({{\rm{\mu }}^{\rm{2}}}\)However, you do not know the value of \({\rm{\mu }}\), so you decide to make \({\rm{n}}\)independent measurements \({{\rm{X}}_{\rm{1}}}{\rm{,}}{{\rm{X}}_{\rm{2}}}{\rm{, \ldots ,}}{{\rm{X}}_{\rm{n}}}\)of the length. Assume that each \({{\rm{X}}_{\rm{i}}}\)has mean \({\rm{\mu }}\) (unbiased measurements) and variance \({{\rm{\sigma }}^{\rm{2}}}\).

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b. For what value of \({\rm{k}}\)is the estimator \({{\rm{\bar X}}^{\rm{2}}}{\rm{ - k}}{{\rm{S}}^{\rm{2}}}\)unbiased for \({{\rm{\mu }}^{\rm{2}}}\)? (Hint: Compute \({\rm{E}}\left( {{{{\rm{\bar X}}}^{\rm{2}}}{\rm{ - k\;}}{{\rm{S}}^{\rm{2}}}} \right)\))

The cumulative frequency and cumulative relativefrequency for a particular class interval are the sum offrequencies and relativefrequencies, respectively, forthat interval and all intervals lying below it. If, forexample, there are four intervals with frequencies 9,16, 13, and 12, then the cumulative frequencies are 9,25, 38, and 50, and the cumulative relative frequenciesare .18, .50, .76, and 1.00. Compute the cumulativefrequencies and cumulative relative frequencies for thedata of Exercise 24.

a. Let aand bbe constants and let\({y_i} = a{x_i} + b\)fori=1, 2, . . . , n. What are the relationships between\(\bar x\)and\(\bar y\)and between\(s_x^2\)and\(s_y^2\)?

b. A sample of temperatures for initiating a certain chemical reaction yielded a sample average (掳C) of 87.3 and a sample standard deviation of 1.04. What are the sample average and standard deviation measured in 掳F? (Hint:\(F = \frac{9}{5}C + 32\))

Every corporation has a governing board of directors. The number of individuals on a board varies from one corporation to another. One of the authors of the article 鈥淒oes Optimal Corporate Board Size Exist? An Empirical Analysis鈥 (J. of Applied Finance, 2010: 57鈥69) provided the accompanying data on the number of directors on each board in a random sample of 204 corporations.

No. directors: 4 5 6 7 8 9

Frequency: 3 12 13 25 24 42

No. directors: 10 11 12 13 14 15

Frequency: 23 19 16 11 5 4

No. directors: 16 17 21 24 32

Frequency: 1 3 1 1 1

a. Construct a histogram of the data based on relative frequencies and comment on any interesting features.

b. Construct a frequency distribution in which the last row includes all boards with at least 18 directors. If this distribution had appeared in the cited article, would you be able to draw a histogram? Explain.

c. What proportion of these corporations have at most 10 directors?

d. What proportion of these corporations have more than 15 directors?

The article cited in Example 1.2 also gave the accompanying strength observations for cylinders:

6.1

5.8

7.8

7.1

7.2

9.2

6.6

8.3

7.0

8.3

7.8

8.1

7.4

8.5

8.9

9.8

9.7

14.1

12.6

11.2


a. Construct a comparative stem-and-leaf display(see the previous exercise) of the beam and cylinder data, and then answer the questions in parts(b)鈥(d) of Exercise 10 for the observations oncylinders.

b. In what ways are the two sides of the display similar? Are there any obvious differences between the beam observations and the cylinder observations?
c. Construct a dotplot of the cylinder data.

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