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Allowable mechanical properties for structural design of metallic aerospace vehicles requires an approved method for statistically analyzing empirical test data. The article 鈥淓stablishing Mechanical Property Allowables for Metals鈥 (J. of Testing and Evaluation, 1998: 293鈥299) used the accompanying data on tensile ultimate strength (ksi) as a basis for addressing the difficulties in developing such a method.

122.2 124.2 124.3 125.6 126.3 126.5 126.5 127.2 127.3

127.5 127.9 128.6 128.8 129.0 129.2 129.4 129.6 130.2

130.4 130.8 131.3 131.4 131.4 131.5 131.6 131.6 131.8

131.8 132.3 132.4 132.4 132.5 132.5 132.5 132.5 132.6

132.7 132.9 133.0 133.1 133.1 133.1 133.1 133.2 133.2

133.2 133.3 133.3 133.5 133.5 133.5 133.8 133.9 134.0

134.0 134.0 134.0 134.1 134.2 134.3 134.4 134.4 134.6

134.7 134.7 134.7 134.8 134.8 134.8 134.9 134.9 135.2

135.2 135.2 135.3 135.3 135.4 135.5 135.5 135.6 135.6

135.7 135.8 135.8 135.8 135.8 135.8 135.9 135.9 135.9

135.9 136.0 136.0 136.1 136.2 136.2 136.3 136.4 136.4

136.6 136.8 136.9 136.9 137.0 137.1 137.2 137.6 137.6

137.8 137.8 137.8 137.9 137.9 138.2 138.2 138.3 138.3

138.4 138.4 138.4 138.5 138.5 138.6 138.7 138.7 139.0

139.1 139.5 139.6 139.8 139.8 140.0 140.0 140.7 140.7

140.9 140.9 141.2 141.4 141.5 141.6 142.9 143.4 143.5

143.6 143.8 143.8 143.9 144.1 144.5 144.5 147.7 147.7

a. Construct a stem-and-leaf display of the data by first deleting (truncating) the tenths digit and then repeating each stem value five times (once for leaves 1 and 2, a second time for leaves 3 and 4, etc.). Why is it relatively easy to identify a representative strength value?

b. Construct a histogram using equal-width classes with the first class having a lower limit of 122 and an upper limit of 124. Then comment on any interesting features of the histogram.

Short Answer

Expert verified

a. The stem and leaf display for the provided scenario is,

12

2

12

445

12

6667777

12

889999

13

00011111111

13

222222222233333333333333

13

44444444444444444455555555555555555555

13

6666666666667777777777

13

888888888888999999

14

0000001111

14

2333333

14

444

14

77

Unit: 12|2=122.2

b.

The histogram is:

It can be observed from the above histogram that the distribution is approximately bell-shaped.

The center lies in the interval 134-136 which can be estimated as 135.

The dispersion is not insignificant and there are no outliers present.

Step by step solution

01

Given information

The data on tensile ultimate strength (ksi) as a basis for addressing the difficulties in developing is provided.

02

Construct a stem and leaf diagram and comment

a. A stem-and-leaf display provides a visual representation of the dataset.

In this case, the values are first changed by truncating the decimal number and hence obtaining the three-digit number values.

The steps to construct a stem-and-leaf for the obtained values are as follows,

1) Select the leading digit for the stem(two values- at hundreds and tens place) and trailing digits for the leaves (at one place).

2) Represent the stem digits vertically and similarly the trailing digits corresponding to the stem digits.

3) follow the rule for describing the leaves 鈥 鈥渆ach stem value five times (once for leaves 1 and 2, a second time for leaves 3 and 4鈥

3) Mention the units for the display.

The stem and leaf display for the provided scenario is,

12

2

12

445

12

6667777

12

889999

13

00011111111

13

222222222233333333333333

13

44444444444444444455555555555555555555

13

6666666666667777777777

13

888888888888999999

14

0000001111

14

2333333

14

444

14

77

Unit: 12|2=122

From the above display, it is easy to identify a representative strength value as the data is symmetric.

03

Construct a histogram and comment on the features

b.

The first class has a lower limit of 122.

The first-classhas anupper limit of 124.

Thus, the classes are obtained as 122-124,124-126,126-128,鈥,146-148.

By counting the observations under each class, the frequency distribution table is obtained as,

Class

Frequency

122-124

1

124-126

3

126-128

7

128-130

6

130-132

11

132-134

25

134-136

38

136-138

22

138-140

18

140-142

10

142-144

7

144-146

3

146-148

2

The steps to construct a histogram are,

1) Determine the frequency or the relative frequency.

2) Mark the class boundaries on the horizontal axis.

3) Draw a rectangle on the horizontal axis corresponding to the frequency or relative frequency.

The histogram is represented as,

It can be observed from the above histogram that the distribution is approximately bell-shaped.

The centre lies in the interval 134-136 which can be estimated as 135.

The dispersion is not insignificant and there are no outliers present.

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Most popular questions from this chapter

Do running times of American movies differ somehow from running times of French movies? The author investigated this question by randomly selecting 25 recent movies of each type, resulting in the following

running times:

Am: 94 90 95 93 128 95 125 91 104 116 162 102 90

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In a famous experiment carried out in 1882, Michelson,and Newcomb obtained 66 observations on the time it took for light to travel between two locations in Washington, D.C. A few of the measurements(coded in a certain manner) were 31, 23, 32, 36, 22, 26, 27, and 31.

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