/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q13E Allowable mechanical properties ... [FREE SOLUTION] | 91影视

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Allowable mechanical properties for structural design of metallic aerospace vehicles requires an approved method for statistically analyzing empirical test data. The article 鈥淓stablishing Mechanical Property Allowables for Metals鈥 (J. of Testing and Evaluation, 1998: 293鈥299) used the accompanying data on tensile ultimate strength (ksi) as a basis for addressing the difficulties in developing such a method.

122.2 124.2 124.3 125.6 126.3 126.5 126.5 127.2 127.3

127.5 127.9 128.6 128.8 129.0 129.2 129.4 129.6 130.2

130.4 130.8 131.3 131.4 131.4 131.5 131.6 131.6 131.8

131.8 132.3 132.4 132.4 132.5 132.5 132.5 132.5 132.6

132.7 132.9 133.0 133.1 133.1 133.1 133.1 133.2 133.2

133.2 133.3 133.3 133.5 133.5 133.5 133.8 133.9 134.0

134.0 134.0 134.0 134.1 134.2 134.3 134.4 134.4 134.6

134.7 134.7 134.7 134.8 134.8 134.8 134.9 134.9 135.2

135.2 135.2 135.3 135.3 135.4 135.5 135.5 135.6 135.6

135.7 135.8 135.8 135.8 135.8 135.8 135.9 135.9 135.9

135.9 136.0 136.0 136.1 136.2 136.2 136.3 136.4 136.4

136.6 136.8 136.9 136.9 137.0 137.1 137.2 137.6 137.6

137.8 137.8 137.8 137.9 137.9 138.2 138.2 138.3 138.3

138.4 138.4 138.4 138.5 138.5 138.6 138.7 138.7 139.0

139.1 139.5 139.6 139.8 139.8 140.0 140.0 140.7 140.7

140.9 140.9 141.2 141.4 141.5 141.6 142.9 143.4 143.5

143.6 143.8 143.8 143.9 144.1 144.5 144.5 147.7 147.7

a. Construct a stem-and-leaf display of the data by first deleting (truncating) the tenths digit and then repeating each stem value five times (once for leaves 1 and 2, a second time for leaves 3 and 4, etc.). Why is it relatively easy to identify a representative strength value?

b. Construct a histogram using equal-width classes with the first class having a lower limit of 122 and an upper limit of 124. Then comment on any interesting features of the histogram.

Short Answer

Expert verified

a. The stem and leaf display for the provided scenario is,

12

2

12

445

12

6667777

12

889999

13

00011111111

13

222222222233333333333333

13

44444444444444444455555555555555555555

13

6666666666667777777777

13

888888888888999999

14

0000001111

14

2333333

14

444

14

77

Unit: 12|2=122.2

b.

The histogram is:

It can be observed from the above histogram that the distribution is approximately bell-shaped.

The center lies in the interval 134-136 which can be estimated as 135.

The dispersion is not insignificant and there are no outliers present.

Step by step solution

01

Given information

The data on tensile ultimate strength (ksi) as a basis for addressing the difficulties in developing is provided.

02

Construct a stem and leaf diagram and comment

a. A stem-and-leaf display provides a visual representation of the dataset.

In this case, the values are first changed by truncating the decimal number and hence obtaining the three-digit number values.

The steps to construct a stem-and-leaf for the obtained values are as follows,

1) Select the leading digit for the stem(two values- at hundreds and tens place) and trailing digits for the leaves (at one place).

2) Represent the stem digits vertically and similarly the trailing digits corresponding to the stem digits.

3) follow the rule for describing the leaves 鈥 鈥渆ach stem value five times (once for leaves 1 and 2, a second time for leaves 3 and 4鈥

3) Mention the units for the display.

The stem and leaf display for the provided scenario is,

12

2

12

445

12

6667777

12

889999

13

00011111111

13

222222222233333333333333

13

44444444444444444455555555555555555555

13

6666666666667777777777

13

888888888888999999

14

0000001111

14

2333333

14

444

14

77

Unit: 12|2=122

From the above display, it is easy to identify a representative strength value as the data is symmetric.

03

Construct a histogram and comment on the features

b.

The first class has a lower limit of 122.

The first-classhas anupper limit of 124.

Thus, the classes are obtained as 122-124,124-126,126-128,鈥,146-148.

By counting the observations under each class, the frequency distribution table is obtained as,

Class

Frequency

122-124

1

124-126

3

126-128

7

128-130

6

130-132

11

132-134

25

134-136

38

136-138

22

138-140

18

140-142

10

142-144

7

144-146

3

146-148

2

The steps to construct a histogram are,

1) Determine the frequency or the relative frequency.

2) Mark the class boundaries on the horizontal axis.

3) Draw a rectangle on the horizontal axis corresponding to the frequency or relative frequency.

The histogram is represented as,

It can be observed from the above histogram that the distribution is approximately bell-shaped.

The centre lies in the interval 134-136 which can be estimated as 135.

The dispersion is not insignificant and there are no outliers present.

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Most popular questions from this chapter

One piece of PVC pipe is to be inserted inside another piece. The length of the first piece is normally distributed with mean value \({\rm{20}}\) in. and standard deviation \({\rm{.5}}\) in. The length of the second piece is a normal \({\rm{rv}}\)with mean and standard deviation \({\rm{15}}\) in. and \({\rm{.4}}\) in., respectively. The amount of overlap is normally distributed with mean value \({\rm{1}}\) in. and standard deviation \({\rm{.1}}\) in. Assuming that the lengths and amount of overlap are independent of one another, what is the probability that the total length after insertion is between \({\rm{34}}{\rm{.5 }}\) in. and \({\rm{35}}\) in.?

The May 1, 2009, issue of the Mont clarian reported the following home sale amounts for a sample of homes in Alameda, CA that were sold the previous month (1000s of $):

590 815 575 608 350 1285 408 540 555 679

  1. Calculate and interpret the sample mean and median.
  2. Suppose the 6th observation had been 985 rather than 1285. How would the mean and median change?
  3. Calculate a 20% trimmed mean by first trimming the two smallest and two largest observations.
  4. Calculate a 15% trimmed mean.

A sample of 20 glass bottles of a particular type was selected, and the internal pressure strength of each bottle was determined. Consider the following partial sample information:
median = 202.2 lower fourth = 196.0
upper fourth = 216.8

Three smallest observations 125.8 188.1 193.7
Three largest observations 221.3 230.5 250.2


a. Are there any outliers in the sample? Any extreme outliers?
b. Construct a boxplot that shows outliers, and comment on any interesting features.

In a famous experiment carried out in 1882, Michelson,and Newcomb obtained 66 observations on the time it took for light to travel between two locations in Washington, D.C. A few of the measurements(coded in a certain manner) were 31, 23, 32, 36, 22, 26, 27, and 31.

a. Why are these measurements not identical?

b. Is this an enumerative study? Why or why not?

Here is a description from Minitab of the strength datagiven in Exercise 13.


Variable N Mean Median TrMean StDev SE Mean
strength 153 135.39 135.40 135.41 4.59 0.37
Variable Minimum Maximum Q1Q3
strength 122.20 147.70 132.95 138.25

  1. Comment on any interesting features (the quartiles and fourths are virtually identical here).
  2. Construct a boxplot of the data based on the quartiles, and comment on what you see.
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