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Compute the\(90\% \)rank-sum \(CI\) for\({\mu _1} - {\mu _2}\)using the data in Exercise\(11\).

Short Answer

Expert verified

Therefore,confidence interval is

\((16,87).\)

Step by step solution

01

Given.

Given:

Let

\({d_{ij}} = {x_i} - {y_i}\)

where\({x_1},{x_2}, \ldots ,{x_m}\)and\({y_1},{y_2}, \ldots ,{y_n}\)are observed value of continuous distributions that differ only in location but not in shape.

The general form of a\(100(1 - \alpha )\)confidence interval for\({\mu _1} - {\mu _2}\)is

\(\left( {{d_{ij(mn - c + 1)}},{d_{ij(c)}}} \right),\)

Where\({d_{ij(1)}},{d_{ij(2)}} \ldots ,{d_{ij(mn)}}\) are the ordered differences.

Use Appendix Table A.16 to determine values of\(c\).
For\(m = n = 5\)and the Table A.16, for\(90.5\% \)confidence interval,\(c = 21\), the confidence interval is in the form of

\(\left( {{d_{ij(mn - c + 1)}},{d_{ij(c)}}} \right) = \left( {{d_{ij(5 \cdot 5 - 21 + 1)}},{d_{ij(21)}}} \right) = \left( {{d_{ij(5)}},{d_{ij(21)}}} \right)\)

Compute all differences, find\({5^{{\rm{th }}}}\)and\({21^{{\rm{th }}}}\)ordered difference values.

The five smallest ordered differences are

\( - 18, - 2,3,4,16\)

and the five largest ordered differences are

\(136,123,120,107,87.\)

The\({5^{th}}\)and\({21^{th}}\)ordered difference are\(16\)and\(87\), respectively; thus, a\(90.5\% \)confidence interval is

\(\left( {{d_{ij(5)}},{d_{ij(21)}}} \right) = (16,87).\)

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Most popular questions from this chapter

The urinary fluoride concentration (parts per million) was measured both for a sample of livestock grazing in an area previously exposed to fluoride pollution and for a similar sample grazing in an unpolluted region:

Polluted

\(21.3\)

\(18.7\)

\(23.0\)

\(17.1\)

\(16.8\)

\(20.9\)

\(19.7\)

Unpolluted

\(14.2\)

\(18.3\)

\(17.2\)

\(18.4\)

\(20.0\)



Does the data indicate strongly that the true average fluoride concentration for livestock grazing in the polluted region is larger than for the unpolluted region? Use the Wilcoxon rank-sum test at level\(\alpha = .01\).

Suppose that observations X1, X2,…, Xn are made on a process at times 1, 2,…, n. On the basis of this data, we wish to test H0: the Xi’s constitute an independent and identically distributed sequence versus Ha: Xi11 tends to be larger than Xi for i =1,…, n (an increasing trend) Suppose the Xi’s are ranked from 1 to n. Then when Ha is true, larger ranks tend to occur later in the sequence, whereas if H0 is true, large and small ranks tend to be mixed together. Let Ri be the rank of Xi and consider the test statistic D = on i= 1(Ri = i)2.

Then small values of D give support to Ha (e.g., the smallest value is 0 for R1 = 10, R2 = 2,…, Rn= n). When H0 is true, any sequence of ranks has probability 1yn!. Use this to determine the P-value in the case n = 4, d= 2. (Hint: List the 4! rank sequences, compute d for each one, and then obtain the null distribution of D. See the Lehmann book (in the chapter bibliography), p. 290, for more information.).

The following observations are amounts of hydrocarbon emissions resulting from road wear of bias-belted tires under a \(522\;{\rm{kg}}\) load inflated at\(228{\rm{kPa}}\)and driven at \(64\;{\rm{km}}/{\rm{hr}}\) for \(6\) hours ("characterization of Tire Emissions Using an Indoor Test Facility," Rubber Chemistry and Technology, \(1978:7 - 25\)): \(.045,.117,\)\(.062\), and \(.072\). What confidence levels are achievable for this sample size using the signed-rank interval? Select an appropriate confidence level and compute the interval.

The accompanying data refers to concentration of the radioactive isotope strontium-90 in milk samples obtained from five randomly selected dairies in each of four different regions.

1 6.4 5.8 6.5 7.7 6.1

2 7.1 9.9 11.2 10.5 8.8

3 5.7 5.9 8.2 6.6 5.1

4 9.5 12.1 10.3 12.4 11.7

Test at level .10 to see whether true average strontium-90 concentration differs for at least two of the regions.

The article "Measuring the Exposure of Infants to Tobacco Smoke" (New England J. of Medicine, 1984: 1075-1078) reports on a study in which various measurements were taken both from a random sample of infants who had been exposed to household smoke and from a sample of unexposed infants. The accompanying data consists of observations on urinary concentration of cotanine, a major metabolite of nicotine (the values constitute a subset of the original data and were read from a plot that appeared in the article). Does the data suggest that true average cotanine level is higher in exposed infants than in unexposed infants by more than 25 ? Carry out a test at significance level .05.

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