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The accompanying data refers to concentration of the radioactive isotope strontium-90 in milk samples obtained from five randomly selected dairies in each of four different regions.

1 6.4 5.8 6.5 7.7 6.1

2 7.1 9.9 11.2 10.5 8.8

3 5.7 5.9 8.2 6.6 5.1

4 9.5 12.1 10.3 12.4 11.7

Test at level .10 to see whether true average strontium-90 concentration differs for at least two of the regions.

Short Answer

Expert verified

Reject null hypothesis

Step by step solution

01

Kruskal- Wallis test:

The kruskal- wallis test

Test for testing equality of the

\({\mu _i}'s\). The test static is

\(\begin{array}{l}K = \frac{{12}}{{N\left( {N + 1} \right)}}\sum\limits_{i = 1}^I {{J_i}} {\left( {{{\bar R}_i} - \frac{{N + 1}}{2}} \right)^2}\\ = \frac{{12}}{{N\left( {N + 1} \right)}}\sum\limits_{i = 1}^I {\frac{{R_i^2}}{{{J_i}}} - 3} \left( {N + 1} \right)\end{array}\)

When the null hypothesis is true, and either

\(\begin{array}{l}I = 3,{J_i} \ge 6\left( {i = 1,2,3} \right)\\or,\\I > 3,{J_i} \ge 5\left( {i = 1,2,I} \right)\end{array}\)

Test statistic K has chi-squared distribution with I-1 degrees of freedom. The P-value is corresponding are to the right of k under the \(X_{I - 1}^2\)curve

02

solving further:

Two table goes together- point\({x_{ij}}\)in the first table corresponds to the\({r_{ij}}\)rank in the second table.

i

Regions

1

6.4

5.8

6.5

7.7

6.1

2

7.1

9.9

11.2

11.2

8.8

3

5.7

5.9

8.2

8.2

5.1

4

9.5

12.1

10.3

10.3

11.7

i

Ranks

\({r_i}\)

1

6

3

7

10

5

31

2

9

14

17

16

12

68

3

2

4

11

8

1

26

4

13

19

15

20

18

85

03

testing static value:

The test statistic value is,

\(\begin{array}{l}k = \frac{{12}}{{N\left( {N + 1} \right)}}\sum\limits_{i = 1}^I {{J_i}} {\left( {{{\bar R}_i} - \frac{{N + 1}}{2}} \right)^2}\\ = \frac{{12}}{{N\left( {N + 1} \right)}}\sum\limits_{i = 1}^I {\frac{{R_i^2}}{{{J_i}}}} - 3\left( {N + 1} \right)\\ = \frac{{12}}{{20.\left( {20 + 1} \right)}}\left( {\frac{{{{31}^2} + {{68}^2} + {{26}^2} + {{85}^2}}}{5}} \right) - 3 \cdot 21\\ = 14.06\end{array}\)

Degrees of freedom are

\({d_f} = I - 1 = 4 - 1 = 3\)

Critical value at significant level 0.1 is


\(\begin{array}{l}X_{0,1,3}^2 = 6.25\\X_{0,1,3}^2 = 6.25 < 14.06 = K\end{array}\)

Reject null hypothesis

Hence, reject null hypothesis.

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Most popular questions from this chapter

Use the large-sample version of the Wilcoxon test at significance level .05 on the data of Exercise 37 in Section 9.3 to decide whether the true mean difference between outdoor and indoor concentrations exceeds .20.

Both a gravimetric and a spectrophotometric method are under consideration for determining phosphate content of a particular material. Twelve samples of the material are obtained, each is split in half, and a determination is made on each half using one of the two methods, resulting in the following data:

Sample

1

2

3

4

Gravimetric

54.7

58.5

66.8

46.1

Spectrophotometric

55.0

55.7

62.9

45.5

The study reported in 鈥淕ait Patterns During Free Choice Ladder Ascents鈥 (Human Movement Sci., 1983: 187鈥195) was motivated by publicity concerning the increased accident rate for individuals climbing ladders. A number of different gait patterns were used by subjects climbing a portable straight ladder according to specified instructions. The ascent times for seven subjects who used a lateral gait and six subjects who used a four-beat diagonal gait are given.

Lateral 0.86 1.31 1.64 1.51 1.53 1.39 1.09

Diagonal 1.27 1.82 1.66 0.85 1.45 1.24

a. Carry out a test using a 5 .05 to see whether the data suggests any difference in the true average ascent times for the two gaits.

b. Compute a 95% CI for the difference between the true average gait times.

The given data on phosphorus concentration in topsoil for four different soil treatments appeared in the article 鈥淔ertilisers for Lotus and Clover Establishment on a Sequence of Acid Soils on the East Otago Uplands鈥 (N. Zeal. J. of Exptl. Ag., 1984: 119鈥129). Use a distributionfree procedure to test the null hypothesis of no difference in true mean phosphorus concentration (mg/g) for the four soil treatments.

I 8.1 5.9 7.0 8.0 9.0

II 11.5 10.9 12.1 10.3 11.9

III 15.3 17.4 16.4 15.8 16.0

IV 23.0 33.0 28.4 24.6 27.7

Refer to Exercise 33, and consider a confidence interval associate\(Y \ge 15\)d with the sign test: the sign interval.

The relevant hypotheses are now \({H_0}:\tilde \mu = {\tilde \mu _0}\) versus \({H_0}:\tilde \mu \ne {\tilde \mu _0}\)

a. Suppose we decide to reject \({H_0}\)if either or \(Y \le 15\). What is the smallest a for which this equivalent to rejecting \({H_0}\) if P-value \( \le \alpha \)?

b. The confidence interval will consist of all values \({\tilde \mu _0}\) for which \({H_0}\) is not rejected. Determine the CI for the given data, and state the confidence level.

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