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On average, Pierre, an amateur chef, drops three pieces of egg shell into every two cake batters he makes. Suppose that you buy one of his cakes. a. In words, define the random variable X. b. List the values that X may take on. c. Give the distribution of \(X, X \sim\) _____(_____,_____) d. On average, how many pieces of egg shell do you expect to be in the cake? e. What is the probability that there will not be any pieces of egg shell in the cake? f. Let’s say that you buy one of Pierre’s cakes each week for six weeks. What is the probability that there will not be any egg shell in any of the cakes? g. Based upon the average given for Pierre, is it possible for there to be seven pieces of shell in the cake? Why?

Short Answer

Expert verified
X is the number of eggshells in a cake. Its distribution is Poisson(1.5). The probability of no pieces in one cake is about 0.2231; for six cakes, it is (0.2231)^6. Up to 7 pieces is possible.

Step by step solution

01

Define the Random Variable X

The random variable \(X\) is defined as the number of pieces of eggshell found in a single cake made by Pierre.
02

List Possible Values of X

Since \(X\) represents the number of pieces of eggshell in a cake, it can take on non-negative integer values, i.e., \(X = 0, 1, 2, 3, \dots\).
03

Identify the Distribution of X

Given that Pierre drops three pieces of eggshells into every two cakes, the average (mean) number of pieces in one cake is \(\lambda = 1.5\). Therefore, the distribution of \(X\) is Poisson: \(X \sim \text{Poisson}(\lambda)\) where \(\lambda = 1.5\).
04

Calculate the Expected Value of X

The expected value (or the mean) for a Poisson distribution is equal to \(\lambda\), which in this case is 1.5. Therefore, on average, you expect 1.5 pieces of eggshell in a cake.
05

Calculate the Probability of No Eggshell in One Cake

The probability of \(X = 0\) for a Poisson distribution is given by \(P(X = 0) = \frac{e^{-\lambda} \cdot \lambda^0}{0!} = e^{-1.5}\). Calculate \(e^{-1.5}\) to find this probability.
06

Calculate the Probability of No Eggshell in Six Cakes

For six independent events (weeks), if the probability of no eggshell in one cake is \(p\), then the probability of no eggshells in all six cakes is \(p^6\), where \(p = e^{-1.5}\).
07

Discuss the Possibility of Seven Pieces of Eggshell

Although the average number of pieces is 1.5, the Poisson distribution allows any non-negative integer value. Therefore, it is theoretically possible to have 7 pieces, though this would be rare given the distribution characteristics.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Random Variables
In probability and statistics, a random variable is a numerical representation of an outcome from a random process. In simpler terms, think of it as a way to assign numbers to all possible outcomes of an event. For example, when considering Pierre's cake, the random variable \(X\) could represent the number of egg shell pieces in a cake.
Random variables can take on different values. They can be discrete, meaning they have specific, individual numbers they can be, such as whole numbers. In the context of Pierre's cake, \(X\) could be 0, 1, 2, or any other non-negative integer. Each of these represents a possible number of egg shells you might find after baking. Understanding which values a random variable can take helps you predict and calculate the likelihood of those outcomes, which is essential in probability calculations.
Exploring Expected Value
The expected value of a random variable is essentially the average outcome you would expect from many repeated trials of the same process. It gives you a single number that summarizes the whole distribution of a random process.
For Pierre's cakes, if you were to bake many cakes, the expected value is the average number of egg shell pieces that would end up in a single cake. We calculate this for a Poisson distribution using its parameter \(\lambda\), which in Pierre's case is 1.5. Hence, on average, each cake is expected to contain 1.5 pieces of egg shell. This average helps us understand typical outcomes of a random process and sets expectations about what usually happens.
Conducting Probability Calculations
Probability calculations are useful for determining how likely certain events are to occur. When dealing with the Poisson distribution, you can calculate the probability of any given number of occurrences of the event, like finding no egg shell in a cake.
For instance, the probability that there are zero pieces of egg shell in a single cake can be calculated using the formula for the Poisson probability mass function:\[P(X = 0) = \frac{e^{-\lambda} \lambda^0}{0!}\]Here, \(\lambda\) is 1.5, and the calculations will show you the likelihood of this event. Such calculations help in understanding and predicting outcomes of specific interest.
Grasping Independent Events
Independent events in probability are those whose outcomes do not affect one another. In simpler terms, the result of one event does not impact the result of another. Such understanding is crucial in multi-step processes or events.
For example, when considering Pierre's cakes over six weeks, each week's outcome regarding the egg shell number remains unaffected by any other week's result. If you want to find the probability of no egg shells in any of the cakes over these six weeks, you multiply the individual probabilities because they are independent:\[p({\text{no egg shell in all six cakes}}) = (e^{-1.5})^6\]This concept of independent events allows complex probability scenarios to be broken down into manageable parts. Understanding this helps you see how larger sets of data can stem from simpler, individual instances, and can be manipulated to predict and calculate probabilities across multiple scenarios.

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