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Aphid growth on broccoli: This problem and the following one are based on the results of a study by R. Root and A. Olson of population growth for aphids on various host plants.44 The value of r = 0.243 per day is valid for aphids reared on broccoli plants outdoors. The table on the next page describes the growth of an aphid population reared on broccoli plants indoors (in a controlled environment). Time t is measured in days. $$ \begin{array}{|l|c|c|c|c|c|} \hline \text { Time } t & 0 & 1 & 2 & 3 & 4 \\ \hline \text { Population } & 25 & 30 & 37 & 44 & 54 \\ \hline \end{array} $$ Calculate r for this table. Did the aphids fare better indoors or outdoors?

Short Answer

Expert verified
The outdoor growth rate \( r = 0.243 \) is higher than the indoor \( r \approx 0.182 \); aphids fared better outdoors.

Step by step solution

01

Understand the Population Growth Formula

To calculate the growth rate \( r \), we use the exponential growth model formula: \( P(t) = P_0 e^{rt} \), where \( P(t) \) represents the population at time \( t \), \( P_0 \) is the initial population size, \( r \) is the growth rate, and \( e \) is the base of the natural logarithm.
02

Choose Data Points from the Table

Select two points from the table where \( t = 0 \) and \( t = 1 \). These data points are \( P(0) = 25 \) and \( P(1) = 30 \).
03

Substitute the Values into the Formula

For \( t = 0 \), the equation is \( 25 = 25e^{0} \). For \( t = 1 \), substitute into the population formula: \( 30 = 25e^{r \cdot 1} \).
04

Solve for r

Rearrange the equation from Step 3 to solve for \( r \): \( 30 = 25e^{r} \). Divide both sides by 25 to get \( e^{r} = \frac{30}{25} \), which simplifies to \( e^{r} = 1.2 \). Take the natural logarithm of both sides: \( \ln(e^{r}) = \ln(1.2) \). This simplifies to \( r = \ln(1.2) \). Calculating gives \( r \approx 0.182 \).
05

Compare Indoor and Outdoor Growth Rates

Given the indoor \( r \approx 0.182 \) and the outdoor \( r = 0.243 \), compare the two rates to determine which environment had a higher growth rate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Growth Model
The Exponential Growth Model is a powerful concept in understanding how populations grow over time. It is particularly useful when analyzing species survival, insect growth, or even financing in economics. The model is described by the formula: \[ P(t) = P_0 e^{rt} \] where:
  • \( P(t) \) is the population size at time \( t \).
  • \( P_0 \) is the initial population size.
  • \( r \) is the growth rate.
  • \( e \) is the base of the natural logarithm, approximately equal to 2.71828.
This formula assumes continuous and natural population growth, typically observed in environments where resources are not limiting and ideal conditions prevail. Practically, it models how populations can grow rapidly when conditions favor reproduction and survival.
It's crucial to understand that this model assumes no environmental constraints, leading to an idealized scenario. Such models help predict future population sizes and assist in planning for conservation, agricultural output, or understanding ecological dynamics.
Aphid Study
Aphids are small sap-sucking insects that can be found on various host plants, including broccoli. In the study conducted by R. Root and A. Olson, researchers examined aphid population growth under different environmental conditions. The study's significant aspect was comparing indoor and outdoor growth to see how controlled environments affect aphid populations. When reared indoors, aphids were sheltered from predators and harsh weather conditions but were primarily limited by the availability of food. Outdoor populations, however, were exposed to natural elements and biological interactions that could affect their growth rate. Understanding these dynamics helps researchers and farmers manage pest populations and improve agricultural productivity by selecting optimal environments or using control measures to regulate aphid populations efficiently.
Growth Rate Calculation
Calculating the growth rate \( r \) for a population provides insights into how quickly it is increasing or decreasing over time. In the exponential growth model, the growth rate is determined by considering two critical variables from observations: the initial population size \( P_0 \) and the population at a later time \( P(t) \).For the aphid study, researchers observed the population size at two different times: initially (when \( t = 0 \) and \( P_0 = 25 \)) and after one day (when \( t = 1 \) and \( P(t) = 30 \)). By substituting these values into the exponential growth model, the growth rate \( r \) is found by solving:\[ 30 = 25e^{r} \] which simplifies to \( e^{r} = 1.2 \). Taking the natural logarithm of both sides gives:\[ r = \ln(1.2) \] yielding \( r \approx 0.182 \). Through this calculation, we discern how external conditions like indoor control influence growth in comparison with field settings.
Population Dynamics
Population dynamics is a crucial aspect of ecology that explains how populations change over time under various influences. It factors in interactions with the environment, predators, availability of resources, and other ecological variables.In the context of the aphid study, understanding these dynamics involves comparing the growth rates of populations reared indoors and outdoors. The calculated growth rate \( r \approx 0.182 \) for indoor conditions and the previously known value \( r = 0.243 \) for outdoor conditions suggest that aphids grow faster in outdoor environments. Despite the controlled environment indoors, outdoor settings provide additional variables like food abundance and natural competitors that may support rapid population growth.By studying these dynamics, ecologists can develop strategies for managing pests in agricultural systems, ensuring sustainable practices, and optimizing crop yields. It also aids in predicting how populations react to changes in their environments, a critical aspect of conservation biology.

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Most popular questions from this chapter

Growth rate of a tubeworm: A study of the growth rate and life span of a marine tubeworm concludes that it is the longest-lived noncolonial marine invertebrate known. \({ }^{9}\) Since tubeworms live on the ocean floor and have a long life span, scientists do not measure their age directly. Instead, scientists measure their growth rate at various lengths and then construct a model for growth rate in terms of length. On the basis of that model, scientists can find a relationship between age and length. This is a good example of how rates of change can be used to determine a relationship when direct measurement is difficult or impossible. The table following shows for a tubeworm the rate of growth in length, measured in meters per year, at the given length, in meters. $$ \begin{array}{|c|c|} \hline \begin{array}{c} \text { Length in } \\ \text { meters } \end{array} & \begin{array}{c} \text { Growth rate in } \\ \text { meters per year } \end{array} \\ \hline 0 & 0.0510 \\ \hline 0.5 & 0.0255 \\ \hline 1.0 & 0.0128 \\ \hline 1.5 & 0.0064 \\ \hline 2.0 & 0.0032 \\ \hline \end{array} $$ a. Often in biology the growth rate is modeled as a decreasing linear function of length. For some organisms, however, it may be appropriate to model the growth rate as a decreasing exponential function of length. Use the data in the table to decide which model is more appropriate for the tubeworm, and find that model. Give a practical explanation of the slope or percentage decay rate, whichever is applicable. b. Use functional notation to express the growth rate at a length of 0.64 meter, and then calculate that value using your model from part a.

Exponential decay with given initial value and decay factor: Write the formula for an exponential function with initial value 200 and decay factor 0.73. Plot its graph.

Stochastic population growth: Many populations are appropriately modeled by an exponential function, at least for a limited period of time. But there are many factors contributing to the growth of any population, and many of them depend on chance. There are a number of ways to produce stochastic models. We consider one that is an illustration of a simple Monte Carlo method. We want to model a population that is initially 500 and grows at an average rate of 2% per year. To do this we make a table of values for population according to the following procedure. The first entry in the table is for time t = 0, and it records the initial value 500. To get the entry corresponding to t = 1, we roll a die and change the population according to the face that appears, using the following rule. $$ \begin{array}{|c|c|} \hline \begin{array}{c} \text { Face } \\ \text { appearing } \end{array} & \begin{array}{c} \text { Population } \\ \text { change } \end{array} \\ \hline 1 & \text { Down 2\% } \\ \hline 2 & \text { Down } 1 \% \\ \hline 3 & \text { No change } \\ \hline 4 & \text { Up 2\% } \\ \hline 5 & \text { Up 4\% } \\ \hline 6 & \text { Up 9\% } \\ \hline \end{array} $$ To get the entry corresponding to \(t=2\), we roll a die and change the population from \(t=1\), again using the above rule. This procedure is then followed for \(t=3\), and so on. a. Using this procedure, make a table recording the population values for years 0 through 10 . b. Plot the data points from your table and the exponential model on the same screen. Comment on the level of agreement.

Population: A biologist has found the following linear model for the natural logarithm of an animal population as a function of time: $$ \ln N=0.039 t-0.693 . $$ Here \(t\) is time in years and \(N\) is the population in thousands. Find an exponential model for the population.

Decibels: Sound exerts a pressure \(P\) on the human ear. This pressure increases as the loudness of the sound increases. It is convenient to measure the loudness \(D\) in decibels and the pressure \(P\) in dynes per square centimeter. It has been found that each increase of 1 decibel in loudness causes a \(12.2 \%\) increase in pressure. Furthermore, a sound of loudness 97 decibels produces a pressure of 15 dynes per square centimeter. a. Explain why \(P\) is an exponential function of \(D\) and find the growth factor. b. Find \(P(0)\) and explain in practical terms what your answer means. c. Find an exponential model for \(P\) as a function of \(D\). d. When pressure on the ear reaches a level of about 200 dynes per square centimeter, physical damage can occur. What decibel level should be considered dangerous?

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