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Testing for a Linear Correlation. In Exercises 13鈥28, construct a scatterplot, and find the value of the linear correlation coefficient r. Also find the P-value or the critical values of r from Table A-6. Use a significance level of A = 0.05. Determine whether there is sufficient evidence to support a claim of a linear correlation between the two variables. (Save your work because the same data sets will be used in Section 10-2 exercises.)

Revised mpg Ratings Listed below are combined city-highway fuel economy ratings (in mi>gal) for different cars. The old ratings are based on tests used before 2008 and the new ratings are based on tests that went into effect in 2008. Is there sufficient evidence to conclude that there is a linear correlation between the old ratings and the new ratings? What do the data suggest about the old ratings?

Old

16

27

17

33

28

24

18

22

20

29

21

New

15

24

15

29

25

22

16

20

18

26

19

Short Answer

Expert verified

The scatter plot is shown below:

The value of the correlation coefficient is 0.998.

The p-value is 0.000.

There is enough evidence to support the claim that there existsa linear correlation between old and new ratings.

The old ratings were higher than the new ratings for each car.

Step by step solution

01

Given information

The data is recorded for the two variables, old and new ratings.

Old

New

16

15

27

24

17

15

33

29

28

25

24

22

18

16

22

20

20

18

29

26

21

19

02

Sketch a scatterplot

A plot described using a paired set of observations is known as a scatterplot.

It givesa tentative relationship between two variables.

Steps to sketch a scatterplot:

  1. Mark the horizontal for old ratings and the vertical for new ratings.
  2. Mark each point in a pair onto the curve.

The resultant scatterplot is shown below.

03

Compute the measure of the correlation coefficient

The correlation coefficient formula is

\(r = \frac{{n\sum {xy} - \left( {\sum x } \right)\left( {\sum y } \right)}}{{\sqrt {n\left( {\sum {{x^2}} } \right) - {{\left( {\sum x } \right)}^2}} \sqrt {n\left( {\sum {{y^2}} } \right) - {{\left( {\sum y } \right)}^2}} }}\).

Define variable xas old ratings and variable y as new ratings.

The valuesare listedin the table below:

x

y

\({x^2}\)

\({y^2}\)

\(xy\)

16

15

256

225

240

27

24

729

576

648

17

15

289

225

255

33

29

1089

841

957

28

25

784

625

700

24

22

576

484

528

18

16

324

256

288

22

20

484

400

440

20

18

400

324

360

29

26

841

676

754

21

19

441

361

399

\(\sum x = 255\)

\(\sum y = 229\)

\(\sum {{x^2}} = 6213\)

\(\sum {{y^2} = } \;4993\)

\(\sum {xy\; = \;} 5569\)

Substitute the values in the formula:

\(\begin{aligned} r &= \frac{{11\left( {5569} \right) - \left( {225} \right)\left( {229} \right)}}{{\sqrt {11\left( {6213} \right) - {{\left( {255} \right)}^2}} \sqrt {11\left( {4993} \right) - {{\left( {229} \right)}^2}} }}\\ &= 0.998\end{aligned}\)

Thus, the correlation coefficient is 0.998.

04

Step 4:Conduct a hypothesis test for correlation

Definethe actual measure of the correlation coefficient as\(\rho \).

For testing the claim, form the hypotheses:

\(\begin{array}{l}{H_o}:\rho = 0\\{H_a}:\rho \ne 0\end{array}\)

The samplesize is 11 (n).

The test statistic is computed as follows:

\(\begin{aligned} t &= \frac{r}{{\sqrt {\frac{{1 - {r^2}}}{{n - 2}}} }}\\ &= \frac{{0.998}}{{\sqrt {\frac{{1 - {{\left( {0.998} \right)}^2}}}{{11 - 2}}} }}\\ &= 47.363\end{aligned}\)

Thus, the test statistic is 47.363.

The degree of freedom is

\(\begin{aligned} df &= n - 2\\ &= 11 - 2\\ &= 9.\end{aligned}\)

The p-value is computed from the t-distribution table.

\(\begin{aligned} p{\rm{ - value}} &= 2P\left( {T > 47.363} \right)\\ &= 0.000\end{aligned}\)

Thus, the p-value is 0.000.

Since thep-value is less than 0.05, the null hypothesis is rejected.

Therefore, there is enough evidence to conclude that old ratings are linearly correlated with new ratings.

05

Discuss the old ratings

The data suggests that throughout the period, the old ratings were higher than the new rating for each car.

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Most popular questions from this chapter

Explore! Exercises 9 and 10 provide two data sets from 鈥淕raphs in Statistical Analysis,鈥 by F. J. Anscombe, the American Statistician, Vol. 27. For each exercise,

a. Construct a scatterplot.

b. Find the value of the linear correlation coefficient r, then determine whether there is sufficient evidence to support the claim of a linear correlation between the two variables.

c. Identify the feature of the data that would be missed if part (b) was completed without constructing the scatterplot.

x

10

8

13

9

11

14

6

4

12

7

5

y

9.14

8.14

8.74

8.77

9.26

8.10

6.13

3.10

9.13

7.26

4.74

Testing for a Linear Correlation. In Exercises 13鈥28, construct a scatterplot, and find the value of the linear correlation coefficient r. Also find the P-value or the critical values of r from Table A-6. Use a significance level of A = 0.05. Determine whether there is sufficient evidence to support a claim of a linear correlation between the two variables. (Save your work because the same data sets will be used in Section 10-2 exercises.)

22. Crickets and Temperature A classic application of correlation involves the association between the temperature and the number of times a cricket chirps in a minute. Listed below are the numbers of chirps in 1 min and the corresponding temperatures in 掳F (based on data from The Song of Insects, by George W. Pierce, Harvard University Press). Is there sufficient evidence to conclude that there is a linear correlation between the number of chirps in 1 min and the temperature?

Actress

28

30

29

61

32

33

45

29

62

22

44

54

Actor

43

37

38

45

50

48

60

50

39

55

44

33

Confidence Intervals for a Regression Coefficients A confidence interval for the regression coefficient b1 is expressed

\(\begin{array}{l}{b_1} - E < {\beta _1} < {b_1} + E\\\end{array}\)

Where

\(E = {t_{\frac{\alpha }{2}}}{s_{{b_1}}}\)

The critical t score is found using n 鈥(k+1) degrees of freedom, where k, n, and sb1 are described in Exercise 17. Using the sample data from Example 1, n = 153 and k = 2, so df = 150 and the critical t scores are \( \pm \)1.976 for a 95% confidence level. Use the sample data for Example 1, the Stat diskdisplay in Example 1 on page 513, and the Stat Crunchdisplay in Exercise 17 to construct 95% confidence interval estimates of \({\beta _1}\) (the coefficient for the variable representing height) and\({\beta _2}\) (the coefficient for the variable representing waist circumference). Does either confidence interval include 0, suggesting that the variable be eliminated from the regression equation?

Variation and Prediction Intervals. In Exercises 17鈥20, find the (a) explained variation, (b) unexplained variation, and (c) indicated prediction interval. In each case, there is sufficient evidence to support a claim of a linear correlation, so it is reasonable to use the regression equation when making predictions.

Altitude and Temperature Listed below are altitudes (thousands of feet) and outside air temperatures (掳F) recorded by the author during Delta Flight 1053 from New Orleans to Atlanta. For the prediction interval, use a 95% confidence level with the altitude of 6327 ft (or 6.327 thousand feet).

Altitude (thousands of feet)

3

10

14

22

28

31

33

Temperature (掳F)

57

37

24

-5

-30

-41

-54

What is the relationship between the linear correlation coefficient rand the slope\({b_1}\)of a regression line?

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