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The Conditional Covariance Formula. The conditional covariance of Xand Y, given Zis defined byCov(X,Y∣Z)≡E[(X-E[X∣Z])(Y-E[Y∣Z])∣Z]

a) Show thatCov(X,Y∣Z)=E[XY∣Z]-E[X∣Z]E[Y∣Z]

b) Prove the conditional covariance formula Cov(X,Y)=E[Cov(X,Y∣Z)]+Cov(E[X∣Z],E[Y∣Z])

c) Set X=Yin part (b) and obtain the conditional variance formula.

Short Answer

Expert verified

a) It has been shown thatCov(X,Y∣Z)=E[XY∣Z]−E[X∣Z]E[Y∣Z]

b) The conditional covariance formula has been proved

Cov(X,Y∣Z)=E[XY∣Z]−E[X∣Z]E[Y∣Z]

c) The conditional variance formula isVar(Y)=E[Var(Y)∣Z]+Var[E(Y∣Z)]

Step by step solution

01

Given Information (Part a) 

Show thatCov(X,Y∣Z)≡E[(X-E[X∣Z])(Y-E[Y∣Z])∣Z]

02

Explanation (Part a) 

We are given that,

Cov(X,Y∣Z)=E[X−E(X∣Z)(Y−E(Y∣Z)∣Z)]

⇒Cov(X,Y∣Z)=E[XY−XE(Y∣Z)−YE(X∣Z)+E(X∣Z)⋅E(Y∣Z)∣Z]

=E(XY∣Z)−E[XE(Y∣Z)∣Z]−E[YE(X∣Z)∣Z]+E[E(X∣Z)E(Y∣Z)∣Z]

=E[XY∣Z]-E(X∣Z)·E(Y∣Z)-E(Y∣Z)·E(X∣Z)+E[X∣Z]·E[Y∣Z]

=E[XY∣Z]-E[X∣Z]·E[Y∣Z]

03

Final Answer (Part a)

It has been shown thatCov(X,Y∣Z)=E[XY∣Z]−E[X∣Z]E[Y∣Z].

04

Given Information (Part b) 

The conditional covariance formula=Cov(X,Y)=E[Cov(X,Y∣Z)]+Cov(E[X∣Z],E[Y∣Z])

05

Explanation (Part b) 

b) R.H.S.=E[Cov(X,Y∣Z)]+Cov[E(X∣Z),E(Y∣Z)]

Using Result of part (a)

=E[E(XY∣Z)−E(X∣Z)E(Y∣Z)]+E[E(X∣Z)⋅E(Y∣Z)∣Z]−E[E(X∣Z)∣Z]⋅E[E(Y∣Z)∣

=E(XY)−E(X)E(Y)+E(X)⋅E(Y)−E(X)⋅E(Y)

role="math" localid="1647526707691" =E(XY)−E(X)⋅E(Y)

=Cov(X,Y)

06

Final Answer (part b) 

Therefore, the conditional covariance formula Cov(X,Y)=E[Cov(X,Y∣Z)]+Cov(E[X∣Z],E[Y∣Z])has been proved.

07

Given Information (Part c) 

SetX=Yin part (b)

08

Explanation (Part c) 

c) Putting X=Yin result of part (b)

role="math" Cov(X,X)=E[Cov(X,X)∣Z]+Cov[E(X∣Z),E(X∣Z)]

⇒Var(X)=E[Var(X)∣Z]+Var[E(X∣Z)]

SimilarlyVar(Y)=E[Var(Y)∣Z]+Var[E(Y∣Z)]

09

Final Answer 

Therefore, the conditional variance formula isVar(Y)=E[Var(Y)∣Z]+Var[E(Y∣Z)].

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