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If E[X]=1and Var(X)=5find

(a)E[(2+X2)]

(b)Var(4+3X)

Short Answer

Expert verified

a) The value of E2+X2is 14.

b) The value ofVar(4+3X)is45.

Step by step solution

01

Given information (Part a)

E(X)=1

Var(X)=5

ThenE2+X2=?

02

Explanation (Part a) 

We know that

EX2=Var(X)+(E(X))2

=5+1

=6

Calculate the expected value of E2+X2

E(2+X)2=E4+X2+4X

=4+6+4

=14

03

Final Answer (Part a) 

The value of E2+X2is14.

04

Given information (Part b)

E(X)=1

Var(X)=5

ThenVar(4+3x)=?

05

Explanation (Part b)  

We know that,

EX2=Var(X)+(E(X))2

=5+1

role="math" localid="1647519062218" =6

Calculate the variance.

Var(4+3X)=0+9Var(X)

=(95)

=45

06

Final Answer (Part b)  

Hence, the value ofVar(4+3x)is45.

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