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A set of 1000 cards numbered 1 through 1000 is randomly distributed among 1000 people with each receiving one card. Compute the expected number of cards that are given to people whose age matches the number on the card.

Short Answer

Expert verified

One of the people expected to receive a card with a number that matches its age.

Step by step solution

01

Given Information

A set of1000 cards numbered 1 through 1000 is randomly distributed among 1000 people with each receiving one card.

02

Explanation

Xi=1,if theithpersons card number matches his/her age0,otherwise

Xiis a new variable.

Expected one of 1,000people to receive the card which matches its age is,

EXi=11000
03

Explanation

The expected number of cards is,

X=i=11000Xi

E(X)=i=11000EXi

=i=1100011000

=1000*11000

=1

E(X)=1

04

Final Answer

One of the people expected to receive a card,E(X)=1.

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Most popular questions from this chapter

Consider the following dice game: A pair of dice is rolled. If the sum is7,then the game ends and you win 0.If the sum is not 7,then you have the option of either stopping the game and receiving an amount equal to that sum or starting over again. For each value ofi,i=2,...,12, find your expected return if you employ the strategy of stopping the first time that a value at least as large as i appears. What value ofileads to the largest expected return? Hint: Let Xidenote the return when you use the critical value i.To computeE[Xi], condition on the initial sum.

The number of people who enter an elevator on the ground floor is a Poisson random variable with mean 10. If there are N floors above the ground floor, and if each person is equally likely to get off at any one of theN floors, independently of where the others get off, compute the expected number of stops that the elevator will make before discharging all of its passengers.

Let X1,X2,be a sequence of independent and identically distributed continuous random variables. Let N2be such that

X1X2XN-1<XN

That is, Nis the point at which the sequence stops decreasing. Show that E[N]=e.

Hint: First find P{Nn}.

LetU1,U2,...be a sequence of independent uniform(0,1)random variables. In Example 5i, we showed that for 0x1,E[N(x)]=ex, where

N(x)=minn:i=1nUi>x

This problem gives another approach to establishing that result.

(a) Show by induction on n that for 0<x10 and all n0

P{N(x)n+1}=xnn!

Hint: First condition onU1and then use the induction hypothesis.

use part (a) to conclude that

E[N(x)]=ex

A bottle initially contains m large pills and n small pills. Each day, a patient randomly chooses one of the pills. If a small pill is chosen, then that pill is eaten. If a large pill is chosen, then the pill is broken in two; one part is returned to the bottle (and is now considered a small pill) and the other part is then eaten.

(a) Let X denote the number of small pills in the bottle after the last large pill has been chosen and its smaller half returned. Find E[X].

Hint: De铿乶e n + m indicator variables, one for each of the small pills initially present and one for each of the small pills created when a large one is split in two. Now use the argument of Example 2m.

(b) Let Y denote the day on which the last large pills chosen. Find E[Y].

Hint: What is the relationship between X and Y?

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