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Let X1,X2,…be a sequence of independent and identically distributed continuous random variables. Let N≥2be such that

X1≥X2≥⋯≥XN-1<XN

That is, Nis the point at which the sequence stops decreasing. Show that E[N]=e.

Hint: First find P{N≥n}.

Short Answer

Expert verified

PX1≥X2≥…≥XN-1<Xn=1-1(N-1)!N-1N=1(N-2)!N

We have proved thatE[N]=e.

Step by step solution

01

Given Information

X1,X2,…be independent and identically distributed continuous random variables.

Let N≥2be such that X1≥X2≥…≥XN-1<XN

02

Calculation

PX1≥X2≥…≥XN-1<XN

=PX1≥X2≥…≥XN-1PXN>XN-1∣X1≥X2≥…≥XN-1

We known X1≥X2≥…≥XN-1because (N-1)!

we have PX1≥X2≥…≥XN-1=1(N-1)!

PXN>XN-1∣X1≥X2≥…≥XN-1=1-1N=N-1N

PX1≥X2≥…≥XN-1<Xn=1-1(N-1)!N-1N

=1(N-2)!N

03

Final Answer

E[N]=∑N=2∞N1(N-2)!N

=∑N=2∞1(N-2)!

=∑N=0∞1N!

=e.

Therefore,E[N]=e.

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