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Consider3urns. An urn Acontains2white and 4red balls, an urn Bcontains 8white and 4 red balls and urn Ccontains 1white and 3red balls. If 1ball is selected from each urn, what is the probability that the ball chosen from urn Awas white given that exactly 2white balls were selected?

Short Answer

Expert verified

0.636365is the probability that the ball chosen from urn A was white given that exactly two white balls were selected.

Step by step solution

01

Step 1:Given Information

Given that 3urns. An urn localid="1647625690012" Acontains 2 white and 4 red balls, an urn Bcontains eight white and four red balls, and an urn Ccontains one white and three red balls.

02

Step 2:Explanation

Let Xbe the possibility that exactly two White balls are selected i.e.,(W,W,R)localid="1647625926749" (W,R,W)(R,W,W)

p(x)=26×812×34+26×412×14+46×812×14

Let Ybe the possibility that the first ball is white i.e.,(W,W,R)(W,R,W)

p(y)=26×812×34+26×412×14

p(y∣x)=26×812×34+26×412×1426×812×34+26×412×14+46×812×14

=0.1944440.305555

=0.636365

03

Step 3:Final Answer

If one ball is selected from each urn, 0.636365is the probability that the ball chosen from urn localid="1647625714756" Awas white given that exactly two white balls were selected.

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