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If two fair dice are rolled, what is the conditional probability that the first one lands on 6 given that the sum of the dice is i? Compute for all values of ibetween 2and12

Short Answer

Expert verified

P(Ai=2)=0P(Ai=3)=0P(Ai=4)=0P(Ai=5)=0P(Ai=6)=0P(Ai=7)=16P(Ai=8)=15P(Ai=9)=14P(Ai=10)=13P(Ai=11)=12P(Ai=12)=1

Step by step solution

01

Given Information

The number on first dice= 6

Sum of both dice=i.

02

Calculation.

When i = 2,3,4,5,6

Consider that Ais the event that first lands in 6.

P(Ai=2)=0P(Ai=3)=0P(Ai=4)=0P(Ai=5)=0P(Ai=6)=0.

P(Ai=7)=16

P(Ai=8), that isi=8occurs when(2,6)(6,2)(5,3)(3,5)(4,4)

Thus,

P(Ai=9), that isi=9occurs when(3,6)(6,3)(5,4)(4,5)

P(Ai=8)=15P(Ai=9),thatThus,P(Ai=9)=14

P(Ai=10)that is i=10occurs when (4,6)(6,4)(5,5)

Thus,

P(Ai=10)=13

P(Ai=11)that is i=11occurs when(5,6)(6,5)

P(Ai=11)=12

P(Ai=12), that is i=12occurs when (6,6)

Thus,

P(Ai=12)=1

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