/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q29P State when standard additions an... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

State when standard additions and internal standards, instead of a calibration curve, are desirable, and why.

Short Answer

Expert verified

The cause of desirability is described in the below steps

Step by step solution

01

The definition of the question

In this job, That will be discussed when standard additions and internal standards are preferable to a calibration curve.

02

Desirability of standard additions

They are advantageous when the sample matrix is unknown or difficult to duplicate, as well as when unexpected matrix effects are anticipated.

03

Desirability of internal standards

They are advantageous when instrument conditions vary from turn to turn and they are added to an unknown sample matrix at the start when uncontrolled and severe sample loss occurs.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Standard addition graph. Allicin is a ~0.4wt%component in garlic with antimicrobial and possibly anticancer and antioxidant activity. It is unstable and therefore difficult to measure. An assay was developed in which the stable precursor alliin is added to freshly crushed garlic and converted to allicin by the enzyme alliinase found in garlic. Components of the garlic are extracted and measured by chromatography. The chromatogram shows standard additions reported as mg alliin added per gram of garlic. The chromatographic peak is allicin from the conversion of alliin.

(a)The standard addition procedure has a constant total volume. Measure the responses in the figure and prepare a graph to find how much alliin equivalent was in the unspiked garlic. The units of your answer will be mg alliin/g garlic. Find the 95%confidence interval, as well.

(b) Given that2molof alliin are converted to1molof allicin, find the allicin content of garlic (mg allicin/g garlic) including the95%confidence interval.

Detection limit. A sensitive chromatographic method was developed to measure sub-part-per-billion levels of the disinfectant by-products iodate(IO3-), chlorite(CIO2-), and bromate(BrO3-)in drinking water. As the oxyhalides emerge from the column, they absorption at267nm. For example, each mole of BrO3-+8Br-+6H+R3Br3-+3H2Obromate makes by the reaction

Bromate near its detection limit gave the following chromatographic peak heights and standard deviations (s). For each concentration, estimate the detection limit. Find the mean detection limit. The blank is 0 because chromatographic peak height is measured from the baseline adjacent to the peak. Because blank =0, relative standard deviation applies to both peak height and concentration, which are proportional to each other. Detection limit is 3 s for peak height or concentration.

Internal standard calibration curve. Figure 5-10 is a graph of Ax/Asversus[X]/[S]=(mol%vinylacetateunits)/(mol%ethyleneunits)=q/p in Reaction 5-13.

(d) From the uncertaintyubof the intercept, find the95%confidence interval for the intercept. Does this interval include the theoretical value of zero?

Standard addition. An unknown sample of Ni2+gave a current of 2.36μ´¡in an electrochemical analysis. When 0.500mLof solution containing role="math" localid="1654761474124" 0.0187MNi2+was added to 25.0mLof unknown, the current increased to 3.79μ´¡.

(a) Denoting the initial, unknown concentration as [Ni2+], write an expression for the final concentration, [Ni2+]f, after role="math" 25.0mLof unknown were mixed with 0.500mLof standard. Use the dilution factor for this calculation.

(b) In a similar manner, write the final concentration of added standard Ni2+, designated as [S]f.

(c) Find[Ni2+]in the unknown.

A solution containing3.47mMX(analyte) and1.72mMS(standard) gave peak areas of3473and 10222,respectively, in a chromatographic analysis. Then1.00mLof 8.47mMSwas added to5.00mLof unknownX,and the mixture was diluted to10.00mL. This solution gave peak areas of5428and4431forXandS, respectively.

(a) Calculate the response factor for the analyte.

(b) Find the concentration of S(mM)inthe10.0-mLmixture.

(c) Find the concentration of X(mM)inthe10.0-mLmixture.

(d) Find the concentration ofXintheorignalunknown.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.