91Ó°ÊÓ

Allicin is a $~0.4\mathrm{wt}\%$

component in garlic with antimicrobial

The chromatographic peak is allicin from the conversion of alliin.

$95\%$of confidence interval have to be found.

$2\mathrm{mol}$of alliin are converted to $1\mathrm{mol}$of allicin

It is necessary to graph the allilin equivalent in unspiked garlic and get the $95\%$

confidence interval.

Concept introduction:

The graph will be drawn using the below equation: role="math" localid="1654855448601" $\mathrm{Plot}\underset{\mathrm{Function}\mathrm{to}\mathrm{plot}\mathrm{on}\mathrm{y}-\mathrm{axis}}{\underset{ÁåŸ}{{\mathrm{l}}_{\mathrm{s}+\mathrm{x}}+\mathrm{X}\left(\frac{\mathrm{V}}{{\mathrm{V}}_0}\right)}}$$\mathrm{versus}{\mathrm{l}}_{\mathrm{x}}+\frac{{\mathrm{l}}_{\mathrm{x}}}{{\left[\mathrm{X}\right]}_{\mathrm{i}}}$$\underset{\mathrm{function}\mathrm{to}\mathrm{plot}\mathrm{on}\mathrm{x}-\mathrm{axis}}{\underset{ÁåŸ}{{\left[\mathrm{S}\right]}_{\mathrm{i}}\left(\frac{{\mathrm{V}}_{\mathrm{s}}}{{\mathrm{V}}_0}\right)}}$

Here$\mathrm{X}-$intercept is${\left[\mathrm{X}\right]}_{\mathrm{i}}$

(a)

The allilin equivalent in unspiked garlic had to be graphed, and the $95\%$confidence interval was computed as $8.21Â\pm 0.62\mathrm{mg}\mathrm{alliin}/\mathrm{g}.$

In the above spreadsheet $\mathrm{x}-\mathrm{axis}$has spike $\left(\mathrm{mg}/\mathrm{g}\right)\mathrm{and}{\mathrm{l}}_{\mathrm{s}+\mathrm{x}}$are plotted.

Figure 2 shows $\mathrm{X}-\mathrm{intercept}$$=\frac{-\mathrm{b}}{\mathrm{m}}=8.20006$is the standard deviation of localid="1654856621530" $\mathrm{X}-\mathrm{intercept}=8.21Â\pm 0.62\mathrm{mg}\mathrm{alliing}/\mathrm{g}\mathrm{garlic}.$

The allilin equivalent in unspiked garlic was graphed, and the$95\%$confidence interval was estimated as$8.21Â\pm 0.62\mathrm{mg}\mathrm{alliing}/\mathrm{g}\mathrm{garlic}.$

(b)

Interpretation Introduction

Interpretation:

When $2\mathrm{mol}$of alliin is converted to $1\mathrm{mol}$, the allicin content of garlic $\left(\mathrm{mg}\mathrm{alliin}/\mathrm{g}\mathrm{garlic}\right)$must be computed.

In the first figure, $\mathrm{preadsheetx}-\mathrm{axis}$has spike $\left(\mathrm{mg}/\mathrm{g}\right)\mathrm{and}{\mathrm{l}}_{\mathrm{s}+\mathrm{x}}$are plotted.

In the figure 3,the quantity of allicin in garlic ,when one mole of allicin is given by two moles of allin is:

$\frac{1}{2}\left(162.3/177.3\right)\left(8.21Â\pm 0.62\mathrm{mg}\right)=3.76Â\pm 0.28\mathrm{mg}\mathrm{alliicin}/\mathrm{g}$

The amount of allicin in garlic was determined as $3.8Â\pm 0.3\mathrm{mg}\mathrm{allicin}/\mathrm{g}.$