/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q11P A 0.0450M solution of benzoic a... [FREE SOLUTION] | 91Ó°ÊÓ

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A 0.0450Msolution of benzoic acid has a pH of2.78. CalculatepKafor this acid

Short Answer

Expert verified

The pKa for benzoic acid is=4.20

Step by step solution

01

Define pKa

pKais the number that describes the acidity of a particular molecule. The formula to find thepKa is

pKa=-logKa

02

Reaction of dissociation

C6H5CO2H⇌C6H5CO2-+H+C6H5CO2H=F-10-2.78C6H5CO2-=H+=10-278

03

Calculating the Ka of benzoic acid

Ka=C6H5CO2-H+C6H5CO2HKa=10-2.7820.0450-10-2.78=6.35×10-5

04

Calculating pKa of benzoic acid

Substituting the value of Kain the formula pKa we get

pKa=-logKa=-log6.35×10-5=4.20

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