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Chapter 9: QC E (page 207)

What is the pH of a solution prepared by dissolving 1.23 of

2-nitrophenol (FM 139.11) in 0.250 L?

Short Answer

Expert verified

The pH of 1.23g of 2-nitrophenol in 0.250L is 4.34.

Step by step solution

01

The formula of pH

The formula of pH of a solution:

pH=-logAH+pH=-logH+纬H+

02

Calculate the pH of of 2-nitrophenol in .

Given formula mass = 139.11

Acid-equilibria constant = 139.11

Mass of 2-nitrophenol = 1.23 g

Volume of 2-nitrophenol = 0.250 L

The formal concentration is MHA.

MHA=1.23g/139.11g/mol0.250L=0.0354MHA鈬�H++A-0.035400-x+x+x(0.0354-x)xxKa=x20.0354-x5.89脳10-8M=x20.0354-xx鈮�0.0354-x5.89脳10-8x=4.57脳10-5M

The of 2-nitrophenol,

pH=-logH+pH=-log4.57脳10-5MpH=4.34

Thus, the pH of 1.23g of 2-nitrophenol in 0.250L is 4.34

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