/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q12P A 0.0450Msolution of HA is 0.6... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A 0.0450Msolution of HAis 0.60%dissociated. CalculatepKafor this acid.

Short Answer

Expert verified

The pKa for HA is=5.79

Step by step solution

01

Define pKa

pKais the number that describes the acidity of a particular molecule. The formula to find the pKa is

role="math" localid="1654857717351" pKa=-logKa

02

Reaction of HA dissociation

HA⇌H++A-HA=0.0450-xH+=A-=x

03

Fraction of dissociation

Substituting the value of aand F in equation

a=xF=0.0060⇒x=a×Fx=0.0060×0.0450

04

Calculating the value of  Ka

By using the formulaKa=x2F-x

Substituting the value ofxand F we get

Ka=x2F-xKa=0.0060×0.045020.0450-0.0060×0.0450=1.6×10-6

05

 Step 5: Finding the value of pKa

Substituting the value of Kain the formula role="math" localid="1654858632522" pKawe get

pKa=-logKa=-log1.6×10-6=5.79

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.