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Chapter 9: Q8P (page 208)

Find theand concentrations of (CH3)3Nand (CH3)3NH+in 0.060Mtrimethylammonium chloride.

Short Answer

Expert verified

pH=5.51

Concentration of

CH32N=H+=3.09脳10-0CH32NH+=0.060M

Step by step solution

01

Step: Definition of pH

pH is defined as a quantitative measure of acidity and basicity. Compounds having pH more than 7 is acidic in nature while pH when shown above than 7 is basic in nature. When pH comes 7 , compound is said to be neutral.

02

Step: Consider the reaction of disassociation.

CH33NH+鈬�CH33N+H+(CH3)3NH+=0.060-xCH33N=H+=x

The value of Ka=1.59脳10-10

03

Calculate x value.

The value of x can be calculated as follows:

Ka=x20.060-xpH=-logH+=-log(3.09脳10-6)=5.51

04

Calculate pH

pH=-logH+=-log3.09脳10-6=5.51

05

Concentration of [CH33 NH+].

CH33NH+=0.060-xCH33NH+=0.060-3.09脳10-6CH33NH+=0.060M

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