/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q31P Why does buffer capacity increas... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Why does buffer capacity increase as a solution becomes very acidic (pH ≈ 1) or very basic (pH ≈ 13)?

Short Answer

Expert verified

At a very low pH, i.e., very acidic (pH ≈ 1) or at a very high pH, i.e., very basic (pH ≈13), the buffer capacity increases as it resists changes in pH by either absorbing or desorbing H+ and OH-ions.

Step by step solution

01

Definition of buffer capacity

Buffer capacity is a quantitative measure of how much a solution is reluctant to pH changes when strong acid or base is added. The more resistant the solution is to pH change, the greater the buffer capacity.

02

Impact on buffer capacity when pH is very acidic or very basic

At very low or very high pH values, there are high acid or base concentrations in a solution. So, adding a little bit of acid or base in that solution would have nearly no effect.

Also, we can consider the following:

  1. At low pH ⇒buffer isH3O+/H2O
  2. At high pH ⇒buffer is H2O/OH-
03

Conclusion

Buffer capacity increases as a solution become very acidic or very basic. A buffer is most effective in resisting changes in pH when pH ≈ 1 or ≈ 13. Buffer capacity increases at high pH (and at low pH), simply because there is a high concentration of OH- at high pH (and H+ at low pH). Hence, adding a small amount of acid or base to a large amount of OH- (or H+) will not have a large effect on pH.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Interpreting spectral data. The graph shows the H-nuclear magnetic resonance chemical shift of theH2 proton on pyridine as a function of pHChemical shift is related to the environment of a proton in a molecule. If the environment changes, the chemical shift changes. Suggest an explanation for why the chemical shift changesbetween low and high Estimate pK2 for pyridinium ion(C5H5NH+)

A solution with an ionic strength of 0.10Mcontaining 0.0100Mphenylhydrazine has a pH of 8.13. Using activity coefficients correctly, find pKafor the phenylhydrazinium ion found in phenylhydrazine hydrochloride. Assume that YBH+=0.80

Calculate the pH of a solution prepared by mixing 0.0800mol of chloroacetic acid plus0.0400mol of sodium chloroacetate in1.00L of water.

(a) First do the calculation by assuming that the concentrations of HA andA- equal their formal concentrations.

(b) Then do the calculation, using the real values of and in the solution.

(c) Using first your head, and then the Henderson-Hasselbalch equation, find the pH of a solution prepared by dissolving all the following compounds in one beaker containing a total volume of1.00L:0.180molCICHCOO2H,0.020molCICHCHO2Na20.080molHNO3,and0.080molCa(OH)2. Assume thatCa(OH)2 dissociates completely.

BH+ClO4- is a salt formed from the base B (Kb= 1.00×10-4)and perchloric acid. It dissociates into BH+, a weak acid, and ClO4-, which is neither an acid nor a base. Find the pH of 0.100 M BH+ClO4-.

A buffer was prepared by dissolving 0.100 mole of the weak acid HA(Ka=1.00×10-5)plus 0.050 mole of its conjugate baseNa+A-in 1.00 L. Find the pH

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.