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Calculate the pH of a solution prepared by mixing 0.0800mol of chloroacetic acid plus0.0400mol of sodium chloroacetate in1.00L of water.

(a) First do the calculation by assuming that the concentrations of HA andA- equal their formal concentrations.

(b) Then do the calculation, using the real values of and in the solution.

(c) Using first your head, and then the Henderson-Hasselbalch equation, find the pH of a solution prepared by dissolving all the following compounds in one beaker containing a total volume of1.00L:0.180molCICHCOO2H,0.020molCICHCHO2Na20.080molHNO3,and0.080molCa(OH)2. Assume thatCa(OH)2 dissociates completely.

Short Answer

Expert verified

a) The pH is 2.56.

b) The pH is2.61 .

c) The pH is 2.86.

Step by step solution

01

Concept used.

The pH of the buffer determined by the concentration ratio of A-and HA by the following Henderson-Hasselbalch equation:pH=pKa+logA-/HA

02

First do the calculation by assuming that the concentrations of HA and A-  equal their formal concentrations.

a)

The pH,

pH=pKa+logA-/HApH=pKa+logsodiumchloroacetate/chloroaceticacodpH=2.865+log0.04/0.08=2.56

03

The calculation using the real values of HA and  A- in the solution.

b)

Calculate the pH by using the real values of HA and A-:

Ka=H+A-HA=H+(0.04-H+0.08-H+H+=2.48×103MpH=-logH+=-log2.48×103=2.61

04

The pH of a solution prepared by dissolving all the following compounds in one beaker.

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