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  1. According to equation 25-2if all conditions are constant, but particle size is reduced from3渭尘to0.7渭尘by what factor must pressure be increased to maintain constant linear velocity?
  2. If all conditions except pressure are constant, by what factor will linear velocity increase if column pressure is increased by a factor of 10?
  3. With 0.7渭尘particles in a 9cm50column, increasing pressure from 70MPato700MPa decreased analysis time by approximately a factor of 10while increasing plate count from
  4. 12000to4500059Explain why small particles permit faster flow without losing efficiency or,in this case,with improved efficiency.

Short Answer

Expert verified

Must pressure be increased to maintain constant linear velocity.

If all conditions except pressure are constant, by what factor will linear velocity.

small particles permit faster flow without losing efficiency or,in this case,with improved efficiency.

The equation25-2

p=f.uv.n.L.蟺谤2.dp2

If all conditions except pressure are constant.

a)18.37timesgreaterb)10times

c) The small particles permit 10-fold faster flow without losing efficiency because small particles has faster transfer than large particles. So, velocity for maximum efficiency (highest plate number) increases.

Step by step solution

01

define constant linear

a) Must pressure be increased to maintain constant linear velocity.

The equation25-2

p=f.uv.n.L蟺谤2.dp2

If all conditions are constant, but particle size (dp)is reduced from3mmto 0.77mmthe factor by the pressure must be increased to maintain constant linear velocity is:

p2p1=d12d22=320.72=18.37

So, pressure must be18.37times greater.

b)If all conditions except pressure are constant, by what factor will linear velocity (uv).

If all conditions except pressure are constant, the factor by linear velocity will increase if column pressure is increased by a factor of 10is10because according to the equation in task a), we see that pressure is proportional to the velocity.

02

particles permit

C) small particles permit faster flow without losing efficiency or,in this case,with improved efficiency.

The small particles permit 10-fold faster flow without losing efficiency because small particles has faster transfer than large particles. So, velocity for maximum efficiency (highest plate number) increases.

Hence,a)18.37timesgreaterb)10times

c) The small particles permit 10-fold faster flow without losing efficiency because small particles has faster transfer than large particles. So, velocity for maximum efficiency (highest plate number) increases.

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Most popular questions from this chapter

In monolithic columns60 the stationary phase is a single porous piece of silica or polymer filling the entire column and synthesized within the column from liquid precursors. Monolithic columns offer similar plate height to HPLC particles, but with less resistance to flow. Therefore, faster flow or longer columns can be used. The figure shows separation of isotopic molecules on a long monolithic column. Packed columns have too much resistance to flow to be made so long.

Separation of isotopic molecules on a 440-cm-long monolithic C18-silica column eluted withCH3CN/H2O(30: 70 vol/vol) at 308C. [Data from K. Miyamoto, T. Hara, H. Kobayashi, H. Morisaka, D. Tokuda, K. Horie, K. Koduki, S. Makino, O. Nu帽ez, C. Yang, T. Kawabe, T. Ikegami, H. Takubo, Y. Ishihama, and N. Tanaka, 鈥淗igh-Efficiency Liquid Chromatographic Separation Utilizing Long Monolithic Silica Capillary Columns,鈥 Anal. Chem. 2008, 80, 8741.]

(a) Unretained thiourea is eluted in 41.7 min. Find the linear velocity ux (mm/s).

(b) Find the retention factor k forC6D6

(c) Find the plate number N and plate height forC6D6

(d) Assuming that the peak widths forC6H5Dand C6D6are the same as that of C6D6, find the resolution of C6H5Dand C6D6.

(f) If we just increased the column length to increase N, what value of N and what column length would be required for a resolution of 1.000?

(g) Without increasing the length of the column, and without changing the stationary phase, how might you improve the resolution?

(h) When the solvent was changed fromCH3CN/H2O(30:70 vol/vol) toCH3CN/CH3OH/H2O(10:5:85), the relative retention for C6H5D andC6D6increased to 1.0088 and the retention factor for C6H6 changed to 17.0. If the plate number were unchanged, what would be the resolution?

A known mixture of compounds A and B gave the following HPLC results:

A solution was prepared by mixing 12.49mgof Bplus 10.00mLof unknown containing just and diluting to 25.00mL. Peak areas of 5.97and 6.38were observed for AandB, respectively. Find the concentration of A(mg/mL)in the unknown.

a. Why is high pressure needed in HPLC?

b. For a given column length , why do smaller particles give a higher plate number?

c. What is bonded phase in liquid chromatography?

A reversed-phase separation of a reaction mixture calls for isocratic elution with 48%methanol 52%water. If you want to change the procedure to use acetonitrile/water, what is a good starting percentage of acetonitrile to try?

Two peaks emerge from a reversed-phase chromatography column as sketched in the illustration.

According to Equation 23-33, resolution is given by

Resolution=N4(-1)(k21+k2)

where Nis plate number, is relative retention (Equation23-20), and k2 is the retention factor for the more retained component (Equation 23-16).

(a) If you decrease the amount of organic solvent in the mobile phase, you will increase retention. Sketch the chromatogram if retention factors increase but Nand are constant.

(b) If you change the solvent type or the stationary phase, you will change the relative retention. Sketch the chromatogram ifincreases but Nandk1are constant.

(c) If you decrease particle size or increase column length, you can increase the plate number. Sketch the chromatogram if Nincreases by (i) decreasing particle size and (ii) increasing column length. Assume and k2are constant.

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