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A known mixture of compounds A and B gave the following HPLC results:

A solution was prepared by mixing 12.49mgof Bplus 10.00mLof unknown containing just and diluting to 25.00mL. Peak areas of 5.97and 6.38were observed for AandB, respectively. Find the concentration of A(mg/mL)in the unknown.

Short Answer

Expert verified

The concentration of Ais 0.418mg/mL..

Step by step solution

01

Definition of compound.

A compound is a substance made up of two or more chemical components that have been chemically bonded together. Covalent bonds and ionic bonds are two typical forms of bonds that hold components in a compound together. In any compound, the components are always present in set ratios.

02

The concentration of A(mg/mL) in the unknown.

PeakareaofAis5.97.PeakareaofBis6.38.AreaAA=FAreaBB10.861.03=F4.371,16F=10.86|1.03||1.16]4.37=12.59764.5011=2.789=2.7925.00mListhetotalvolumeoftheunknownsolution.TheadditionalweightofBis12.49g.ThetotalvolumeofAthathasbeenaddedis10mL.Asdemonstratedbelow,theconcentrationofBintheunknownsolutionmaybedetermined.

12.49g/25.00ml=0.4996g/mL

Theconcentrationofisrepresentedbelow.ArcaAA=FArcaBB5.97A=2.796.380.4996A=5.972.7910.4996]6.38=2.98261217.8002=0.1675g/mLTheconcentrationofAintheinitialunknownsolutionisdeterminedtobeasfollows:Ainoriginalunknown=25.0010.00(0.167mg/mL)=0.418mg/mLTherefore,theconcentrationofAintheunknownisfoundas0.418mg/mL.

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Most popular questions from this chapter

A bonded stationary phase for the separation of optical isomers has the structure

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