/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q12P (a). Sketch a graph of the van D... [FREE SOLUTION] | 91影视

91影视

(a). Sketch a graph of the van Deemnter equation (plate height versus linear flow rate).what would the curve look like if the multiple path term were 0? If the longtitundinal diffusinal diffusion term were 0?

(b). Explain why the van Deemter curve for 1.8渭尘particles in figure 25-3is nearly flat at high flow rate.what can you say about each of the terms in the van Deemeter equation for 1.8渭尘particles.

(c). Explain why the 2.7渭尘superficially porous particle enables separations similar to those achieved by 1.8渭尘totally porous particles,but the superficially porous particle requires lower pressure.

Short Answer

Expert verified

a) Sketch a graph of the van Deemnter.

b) Comparing the van Deemter curve of the particles in Figure to the graph

c) Superficially porous particles have a diameter non porous silica core.

Step by step solution

01

Sketch a graph of the van Deemnter 

The van Deemter equation was graphed to help visualise each term in the equation. Figure 24-3 was then examined using the van Deemter equation and its implications.

The figure below shows the graph of the van Deemter equation when the multiple paths term ( A) is , when the longitudinal diffusion term ( B) is , when the equilibration time term (C ) is constant, and when all terms are .

02

Comparing the van Deemter

b) why the van Deemter curve

Comparing the van Deemter curve of the 1.8渭尘particles in Figure 24-3to the graph in (a), we can see that the graph that it most resembles is the graph of c=0. Although not obvious from the graphs, the equation of the curve of 1.8渭尘particles has a small multiple paths term (A ) relative to that of the other larger particles in the graph.

Based on the graph, the curve of the particles plateaus at the smallest plate height ( H) compared to the other graphs. The reduction in plate heights can be related to the decrease in the band spreading due to multiple flow paths.

Given this relationship, the decrease in the H plateau value of the particles means that there is a decrease in A as the particle size decreases.

c) superficially porous particle

Superficially porous particles have a 5渭尘diameter non porous silica core. Compared to other fully porous particles with a larger radii, superficially porous particles can perform at the same level or better.

This is due to the structure of superficially porous particles, having a 0.25 thick porous silica layer on the outside of its 5渭尘diameter non porous silica core

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A reversed-phase separation of a reaction mixture calls for isocratic elution with 48%methanol 52%water. If you want to change the procedure to use acetonitrile/water, what is a good starting percentage of acetonitrile to try?

The figure shows the separation of two enantiomers on a chiral stationary phase.


Sepation of enantiomers of Ritalin by HPLC with a chiral stationary phase.[Data from R.Bakhitar,L.Ramos,and F.L.S.Tse, 鈥淨uantification of methlylphenidate in plasma using chiral Liquid-chromatography/Tandem mass spectrometry: Application to Toxicokinetric studies,鈥滱nal Chim Acta 2002,469,261.]

(a)From trandw1/2 find N for each peak.

(b) Fromtrandw1/2find the resolution.

(c)Giventm=1.62min, use Equation23-23with the average N to predict the resolution.

A known mixture of compounds A and B gave the following HPLC results:

A solution was prepared by mixing 12.49mgof Bplus 10.00mLof unknown containing just and diluting to 25.00mL. Peak areas of 5.97and 6.38were observed for AandB, respectively. Find the concentration of A(mg/mL)in the unknown.

(a) When you try separating an unknown mixture byreversed-phase chromatography with 48%acetonitrile 50%water,the peaks are too close together and are eluted in the range k = 2- 6Should you use a higher or lower concentration of acetonitrile in thenext run?

(b) When you try separating an unknown mixture by normal-phasechromatography with 50%hexane50% methyl t-butyl ether, thepeaks are too close together and are eluted in the range k = 2 - 6Should you use a higher or lower concentration of hexane in thenext run?

What are the general steps in developing as isocratic separation for reversed-phase chromatography with one organic solvent and temperature as variable?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.