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Explain why the change from red to blue in Reaction 12-19 occurs suddenly at the equivalence point instead of gradually throughout the entire titration.

Short Answer

Expert verified

As very small of indicator is introduced into the sample, many of the Mg2+ ions is not bounded with the indicator. Free ions of Mg2+ are preferable for reaction with EDTA than MgIn. Therefore, concentration of MgIn remains constant until all the free Mg2+ ions have been consumed. Only after that MgIn gets chance to react with EDTA. As soon as the reaction starts with the indicator the color change from red to blue. This is the reason that the change from red to blue in Reaction 12-19 occurs suddenly at the equivalence point instead of gradually throughout the entire titration.

Step by step solution

01

Information given

Equation 12-19 is a typical illustration of a titration reaction between Mg2+ and EDTA at pH 10 in presence of calmagite indicator. The reaction is as follows

²Ñ²µÎ™²Ô+EDTA→MgEDTA+Ι²ÔRedColorlessColorlessBlue

02

How the reaction proceeds

Little amount of indicator is induced at the beginning of the experiment. It is added to the colorless Mg2+complex and forms a red complex. After that EDTA is added. This reacts with the Mg2+ solution first. After completion of reaction between Mg2+ and EDTA, the remained indicator sample reacts with EDTA and turns into blue unboundIn.

03

Reason

As very small of indicator is introduced into the sample, many of the Mg2+ ions is not bounded with the indicator. Free ions of Mg2+ are preferable for reaction with EDTA than MgIn . Therefore, concentration of MgIn remains constant until all the free Mg2+ ions have been consumed. Only after that MgIn gets chance to react with EDTA. As soon as the reaction starts with the indicator the color change from red to blue. This is the reason that the change from red to blue in Reaction 12-19 occurs suddenly at the equivalence point instead of gradually throughout the entire titration

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Most popular questions from this chapter

Calculate pCu2+ (to the 0.01 decimal place) at each of the following points in the titration of 50.0 mL of 0.040 0 M EDTA with 0.080 0 M Cu (NO3)2 at pH 5.00: 0.1, 5.0, 10.0, 15.0, 20.0, 24.0, 25.0, 26.0, and 30.0 mL. Make a graph of pCu2+ versus volume of titrant.

Spreadsheet equation for auxiliary complexing agent. Consider the titration of metal M (initial concentration = CM, initial volume = VM) with EDTA (concentration = CEDTA, volume added = VEDTA) in the presence of an auxiliary complexing ligand (such as ammonia). Follow the derivation in Section 12-4 to show that the master equation for the titration is

Ï•=CETDAVETDACMVM=1+Kf"[M]free-[M]free+Kf"[M]freeCMKf"[M]free+[M]free+Kf"[M]free2CETDA

where role="math"> is the conditional formation constant in the presence of auxiliary complexing agent at the fixed pH of the titration (Equation 12-18) and [M]free is the total concentration of metal not bound to EDTA. [M]free is the same as [M] in Equation 12-15. The result is equivalent to Equation 12-11, with [M] replaced by [M]free and Kf replaced by Kf".

Calculate pCu2+ at each of the following points in the titration of 50.00 mL of 0.001 00 M Cu2+ with 0.00100 M EDTA at pH 11.00 in a solution with [NH3] fixed at 1.00 M:

(a) 0 mL(b) 1.00 mL (c) 45.00 mL (d) 50.00 mL (e) 55.00 mL

Pyrocatechol violet(Table 12-3) is to be used as a metal ion indicator in an EDTA titration. The procedure is as follows:

1. Add a known excess of EDTA to the unknown metal ion.

2. Adjust the pH with a suitable buffer.

3. Back-titrate the excess chelate with standard Al3+.

From the following available buffers, select the best buffer, and then state what color change will be observed at the end point. Explain your answer.

  1. pH 6–7 (ii) pH 7–8 (iii) pH 8–9 (iv) pH 9–10

Give three circumstances in which an EDTA back titration might be necessary

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