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Calculate pCu2+ (to the 0.01 decimal place) at each of the following points in the titration of 50.0 mL of 0.040 0 M EDTA with 0.080 0 M Cu (NO3)2 at pH 5.00: 0.1, 5.0, 10.0, 15.0, 20.0, 24.0, 25.0, 26.0, and 30.0 mL. Make a graph of pCu2+ versus volume of titrant.

Short Answer

Expert verified

The values obtained forpCu2+are tabulated below

Volume (mL)

pCu2+

0.1

14.64

5.0

12.84

10.0

12.42

15.0

12.07

20.0

11.64

24.0

10.86

25.0

6.91

26.0

2.98

30.0

2.30

Graph of pCu2+ versus volume of titrant is plotted below

Step by step solution

01

Given Information

Amount of EDTA required for titration = 50 mL of 0.04 M EDTA

Concentration of Cu(NO3)2 required for titration =0.08 M

pH maintained =5

02

EDTA

EDTA is one type of chelating agent also known as Ethylenediaminetetraacetic acid. It is used to treat heavy metal toxicity, neurotoxicity, lead poisoning, coronary artery disease etc. EDTA has applications in different industries like textile, pulp and paper etc. It is used in biochemistry and molecular biology lab.

03

Determine pCu2+

Total concentration of EDTA

Kf'=CuY2-Cu2+EDTA=αY4-Kf=2.9×10-71018.78=1.74×1012

At 0.1 mL Cu (NO3)2

Concentration of EDTA

=25.0mL-0.1mL25.0mL0.04M50.0mL50.1mL=0.04M

Concentration of CuY2-

=0.1mL50.1mL0.08M=1.6×10-4M

Concentration of Cu2+

Cu2+=CuY2-Kf'EDTA=1.6×10-4M1.74×10120.04M=2.3×10-15MpCu2+=-logCu2+=-log2.3×10-15M=14.64

At 25.0 mL Cu (NO3)2

Concentration of CuY2-

=25750.08M=0.027M

Therefore, we can write

0.027-xx2=1.74×1012x=1.24×10-7M

Concentration of Cu2+ = 1.24×10-7 M

pCu2+=-logCu2+=-log1.24×10-7M=6.91

The value of pCu2+ for other volumes were calculated following the above calculations.

The values obtained are tabulated below

Volume (mL)

pCu2+

0.1

14.64

5.0

12.84

10.0

12.42

15.0

12.07

20.0

11.64

24.0

10.86

25.0

6.91

26.0

2.98

30.0

2.30

04

Graph plotting 

Graph of pCu2+ versus volume of titrant is plotted below

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