/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q12D E Calculate the concentration of H... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Calculate the concentration of H2Y2- at the equivalence point in Exercise 12-C

Short Answer

Expert verified

H2Y2- concentration at equivalence point will be 1.1×10-7M

Step by step solution

01

Given Information

With reference to 12-c the following information were given

Amount of EDTA required for titration = 50 mL of 0.04 M EDTA

Concentration of Cu(NO3)2 required for titration =0.08 M

pH maintained =5

02

EDTA

EDTA (Ethylenediaminetetraacetic acid) is one type of chelating agent. It is used to treat heavy metal toxicity, neurotoxicity, lead poisoning, coronary artery disease etc. It is also used in different industries like pulp and paper, textile etc. It has applications in biochemistry and molecular biology lab.

03

Determine the concentration

From 12-C the equivalence point was determined at 1.24×10-7M EDTA concentration

K=K5K6=H+2Y4-H2Y2-H2Y2-=H+2Y4-K5K6H2Y2-=H+2αY4-EDTAK5K6H2Y2-=10-522.9×10-71.24×10-7K5K6H2Y2-=1.1×10-7M

Therefore, H2Y2- concentration at equivalence point will be 1.1×10-7M

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Sulfide ion was determined by indirect titration with EDTA. To a solution containing 25.00 mL of 0.04332 M Cu(ClO4)2 plus 15 mL of 1 M acetate buffer (pH 4.5) were added 25.00 mL of unknown sulfide solution with vigorous stirring. The CuS precipitate was filtered and washed with hot water. Ammonia was added to the filtrate (which contained excess Cu2+) until the blue color of Cu(NH3)42+ was observed. Titration of the filtrate with 0.039 27 M EDTA required 12.11 mL to reach the murexide end point. Calculate the molarity of sulfide in the unknown.

Pyrocatechol violet(Table 12-3) is to be used as a metal ion indicator in an EDTA titration. The procedure is as follows:

1. Add a known excess of EDTA to the unknown metal ion.

2. Adjust the pH with a suitable buffer.

3. Back-titrate the excess chelate with standard Al3+.

From the following available buffers, select the best buffer, and then state what color change will be observed at the end point. Explain your answer.

  1. pH 6–7 (ii) pH 7–8 (iii) pH 8–9 (iv) pH 9–10

Find αZn2+if free, unprotonated [NH3] = 0.02 M.

According to Appendix I, Cu2+ forms two complexes with acetate:

Cu2++CH3CO2−⇌Cu(CH3CO2)+ â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰Î²1(=K1)Cu2++2CH3CO2−⇌Cu(CH3CO2)2 â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰â¶Ä‰Î²2

(a) Referring to Box 6-2, find K2 for the reaction

Cu(CH3CO2)++CH3CO2−⇌Cu(CH3CO2)2(aq) â¶Ä‰â¶Ä‰K2

(b) Consider 1.00 L of solution prepared by mixing 1.00 × 10-4 mol Cu(ClO4)2 and 0.100 mol CH3CO2Na. Use Equation 12-16 to find the fraction of copper in the form Cu2+


Consider the titration of 25.0 mL of 0.020 0 M MnSO4 with 0.010 0 M EDTA in a solution buffered to pH 8.00. Calculate pMn2+ at the following volumes of added EDTA and sketch the titration curve:

(a) 0 mL (b) 20.0 mL (c) 40.0 mL (d) 49.0 mL (e) 49.9 mL (f) 50.0 mL (g) 50.1 mL(h) 55.0 mL (i) 60.0 mL

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.