91影视

Equations and data obtained in order to proceed for calculation are as follows

$\begin{array}{c}C{u}^{2+}+Y^{4鈭�}鈬�Cu{Y}^{2鈭�}\\ K_f={10}^{18.78}=6.03脳{10}^{18}\\ At\text{鈥夆赌夆赌�}pH\text{鈥夆赌夆赌�}11\text{鈥夆赌夆赌�}{伪}_{Y^{4鈭�}}=0.81\text{鈥�}\left(Table\text{鈥�}12鈭�1\right)\\ \log {尾}_1=3.99\\ \log {尾}_2=7.33\\ \log {尾}_3=10.06\\ \log {尾}_4=12.03\end{array}$

The beta(尾) values were obtained from appendix-1 for Cu²⁺ and NH₃

$\begin{array}{c}{伪}_{C{u}^{2+}}=\frac{1}{1+{尾}_1\left(1.00\right)+{尾}_2{\left(1.00\right)}^2+{尾}_3{\left(1.00\right)}^3+{尾}_4{\left(1.00\right)}^4}\\ =9.23脳{10}^{鈭�13}\\ K_f^{\text{'}}={伪}_{Y^{4鈭�}}{K}_f\\ =0.81脳6.03脳{10}^{18}\\ =4.88脳{10}^{18}\\ K_f^{"}={伪}_{C{u}^{2+}}脳K_f^{\text{'}}\\ =9.23脳{10}^{鈭�13}脳4.88脳{10}^{18}\\ =4.51脳{10}^6\end{array}$

Equivalence point=50 mL

The concentration of the remaining productcan be calculated using the following equation

=Fraction remaining 脳 Initial concentration 脳 Dilution factor

If 1 mL solution is added then copper concentration will be

$$\begin{gathered} \begin{array}{c}\left[Cc{u}^{2+}\right]=\left(\frac{50鈭�1}{50}\right)\left(0.001\text{鈥�}M\right)\left(\frac{50}{50+1}\right)\\ =9.61脳{10}^{鈭�4}\text{鈥�}M\end{array} \\ \begin{array}{c}\left[C{u}^{2+}\right]={伪}_{C{u}^{2+}}脳C_{C{u}^{2+}}\\ =\left(9.23脳{10}^{鈭�13}脳9.61脳{10}^{鈭�4}\right)M\\ =8.87脳{10}^{鈭�16}M\end{array} \end{gathered}$$

Therefore, the value of pCu²⁺

^{$\begin{array}{c}pC{u}^{2+}=鈭�\log \left(C{u}^{2+}\right)\\ =鈭�\log \left(8.87脳{10}^{鈭�16}\right)\\ =15.05\end{array}$}