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Calculate [HY3-] in a solution prepared by mixing 10.00 mL of 0.010 0 M VOSO4, 9.90 mL of 0.010 0 M EDTA, and 10.0 mL of buffer with a pH of 4.00

Short Answer

Expert verified

The concentration of HY3- in solution is 4.6×10-11M

Step by step solution

01

Given Information

Volume of VOSO4 taken to prepare solution = 10 mL

Concentration of VOSO4 taken to prepare solution = 0.01M

Volume of EDTA taken to prepare solution = 9.90 mL

Concentration of EDTA taken to prepare solution = 0.01M

Volume of buffer (pH=4) solution taken=10 mL

02

Determine concentration of VO2+ and VOY2-

VO2+=0.129.90.01M=3.34×10−5MVOY2−=9.929.90.01M=3.31×10−3M

Equations and data obtained in order to proceed for calculation are as follows

Kf=1018.7At â¶Ä‰â¶Ä‰pH â¶Ä‰â¶Ä‰4 â¶Ä‰pK6=10.37 for H6Y2+

03

Determine concentration of HY3-

Kf=VOY2−VO2+Y4−Y4−=VOY2−VO2+Kf=3.31×10−33.34×10−5×1018.7=1.98×10−17

K6=H+Y4−HY3−HY3−=10−41.98×10−1710−10.37=H+Y4−K6=4.6×10−11M

Therefore,the concentration of HY3- in solution is 4.6×10-11M

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Most popular questions from this chapter

Spreadsheet equation for auxiliary complexing agent. Consider the titration of metal M (initial concentration = CM, initial volume = VM) with EDTA (concentration = CEDTA, volume added = VEDTA) in the presence of an auxiliary complexing ligand (such as ammonia). Follow the derivation in Section 12-4 to show that the master equation for the titration is

Ï•=CETDAVETDACMVM=1+Kf"[M]free-[M]free+Kf"[M]freeCMKf"[M]free+[M]free+Kf"[M]free2CETDA

where role="math"> is the conditional formation constant in the presence of auxiliary complexing agent at the fixed pH of the titration (Equation 12-18) and [M]free is the total concentration of metal not bound to EDTA. [M]free is the same as [M] in Equation 12-15. The result is equivalent to Equation 12-11, with [M] replaced by [M]free and Kf replaced by Kf".

Calcium ion was titrated with EDTA at pH 11, using Calmagite as indicator (Table 12-3). Which is the principal species of Calmagite at pH 11? What color was observed before the equivalence point? After the equivalence point?

Sulfide ion was determined by indirect titration with EDTA. To a solution containing 25.00 mL of 0.04332 M Cu(ClO4)2 plus 15 mL of 1 M acetate buffer (pH 4.5) were added 25.00 mL of unknown sulfide solution with vigorous stirring. The CuS precipitate was filtered and washed with hot water. Ammonia was added to the filtrate (which contained excess Cu2+) until the blue color of Cu(NH3)42+ was observed. Titration of the filtrate with 0.039 27 M EDTA required 12.11 mL to reach the murexide end point. Calculate the molarity of sulfide in the unknown.

At what pH does αy4-=0.50?

Calculate pCu2+ at each of the following points in the titration of 50.00 mL of 0.001 00 M Cu2+ with 0.00100 M EDTA at pH 11.00 in a solution with [NH3] fixed at 1.00 M:

(a) 0 mL(b) 1.00 mL (c) 45.00 mL (d) 50.00 mL (e) 55.00 mL

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