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Chapter 12: Q1 TY (page 269)

At what pH does 伪y4-=0.50?

Short Answer

Expert verified

At pH 10.35 the value of 伪y4-=0.50

Step by step solution

01

Introduction

The fraction of all free EDTA (in Y4- format) is expressed in terms of 伪Y4-. It can be expressed as

伪Y4-=Y4-H6Y2++H5Y++H4Y+H3Y-+H2Y2-+HY3-+Y4-

02

Given Data

In table 12-1 values of for EDTA at different pH is given.

From the above table the following graph was obtained

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Most popular questions from this chapter

Consider the titration of 25.0 mL of 0.020 0 M MnSO4 with 0.010 0 M EDTA in a solution buffered to pH 8.00. Calculate pMn2+ at the following volumes of added EDTA and sketch the titration curve:

(a) 0 mL (b) 20.0 mL (c) 40.0 mL (d) 49.0 mL (e) 49.9 mL (f) 50.0 mL (g) 50.1 mL(h) 55.0 mL (i) 60.0 mL

Cyanide solution (12.73 mL) was treated with 25.00 mL of Ni2+ solution (containing excess Ni2+) to convert the cyanide into tetracyano nickelate (II):

4CN-+Ni2+鈫�Ni(CN)42-

Excess Ni2+ was then titrated with 10.15 mL of 0.01307 M EDTA. Ni(CN)42-does not react with EDTA. If 39.35 mL of EDTA were required to react with 30.10 mL of the original Ni2+ solution, calculate the molarity of CN- in the 12.73-mL sample.

Consider the titration of 25.0 mL of 0.020 0 M MnSO4 with 0.010 0 M EDTA in a solution buffered to pH 8.00. Calculate pMn2+ at the following volumes of added EDTA and sketch the titration curve:

(a) 0 mL (b) 20.0 mL (c) 40.0 mL (d) 49.0 mL (e) 49.9 mL (f) 50.0 mL (g) 50.1 mL(h) 55.0 mL (i) 60.0 mL

Find 伪Zn2+if free, unprotonated [NH3] = 0.02 M.

What is the predominant form of arginine atpH11? What is the second major species?
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