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Chapter 14: Q76P (page 680)

Identify the compound with a molecular formula C6H10O that gives the following DEPT 13C NMR spectrum:

Short Answer

Expert verified

The compound can be:

Step by step solution

01

DEPT spectrum

It is defined as Distortionless Enhancement by Polarization Transfer in which transfer of polarisation occurs from an excited nucleus to another. It is a type of double resonance program. In this, we can read the multiplicity directly by reducing CH coupling.

02

Identify compound from molecular formula

As per the given molecular formula we can find the number of carbon is 6 and hydrogen is 10 and the oxygen is present and the signal at 220 ppm shows the presence of the ketone having one methyl group and one CH group and three methylene groups.

03

Identify compound by DEPT spectra

As depicted by the DEPT the high-frequency signal is due to the methylene group and CH group showing these groups attached to carbonyl so the compound must be:

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Most popular questions from this chapter

a. Which proton or set of protons in each of the following compounds is the least shielded?

b. Which proton or set of protons in each compound is the most shielded?

Identify each of the following compounds from its molecular formula and its IR and 1H NMR spectra:

a.C5H12O

b. C6H12O2

c. C4H7ClO2

d. C4H8O2

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How many signals would you expect to see in the NMR spectrum of each of the following compounds ?
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