Chapter 5: Q63P (page 224)
For a reaction carried out at 25°C with an equilibrium constant of 1 × 10−3, in order to increase the equilibrium constant by a factor of 10:
a. How much must Δ³Ò° change?
b. How much must Δ±á° change if Δ³§Â° = 0 kcal mol-1 K-1?
c. How much must Δ³§Â° change if Δ±á° = 0 kcal mol-1?
Short Answer
a) Δ³Òo = _RT ln Keq
= - 1.36 kcal/mol
²ú)Δ³Òo = Δ±áo - T Δ³§o
Δ±áo= -1.36 kcal/mol
³¦)Δ³Òo = Δ±áo - T Δ³§o
Δ³§o= 4.56 × 10-3 kcal/(mol deg)


