/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q5-42P 聽Draw the condensed structure f... [FREE SOLUTION] | 91影视

91影视

Draw the condensed structure for each of the following:

a. (Z)-1,3,5-tribromo-2-pentene

b. (Z)-3-methyl-2-heptene

c. (E)-1,2-dibromo-3-isopropyl-2-hexene

d. vinyl bromide

e. 1,2-dimethylcyclopentene

f. diallyl amine

Short Answer

Expert verified

All the structures are drawn using the IUPAC and E, Z nomenclature and they are given below.

Step by step solution

01

Drawing of structures from IUPAC name

We can draw the structures from the IUPAC name of the compound by using the following rules and these are as follows.

  1. Find out the longest chain and do the numbering.

Ex, If a compound is 3-methyl-butan-1-ol, that means the longest chain name is butane.

2. Find out the positions of substituting groups in the longest chain.

Ex- for the above compound, Methyl is attached to the 3rd position and the hydroxyl group is in 1 position of the skeletal chain or the main chain, So, I should be written in the 3rd position and hydroxyl group in the 1st position.

3. 鈥渘鈥 in a compound designated non-branched compound.

4. N, N means the substitution of groups to N of amine groups.

02

E, Z nomenclature

When a double bond has same priority number in the same side, the structure is called Z nomenclature.

When a double bond has same priority number in the Opposite side, the structure is called E nomenclature.

03

Estimation of the structures


All the condensed structures of the compounds are given below.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Given the reaction coordinate diagram for the reaction of A to form G, answer the following questions:

a. How many intermediates are formed in the reaction?

b. Which letters represent transition states?

c. What is the fastest step in the reaction?

d. Which is more stable,AorG?

e. DoesAorEform faster fromC?

f. What is the reactant of the rate-determining step?

g. Is the first step of the reaction exergonic or endergonic?

h. Is the overall reaction exergonic or endergonic?

i. Which is the more stable intermediate?

j. Which step in the forward direction has the largest rate constant?

k. Which step in the reverse direction has the smallest rate constant?

Use what the curved arrows tell you about electron movement to determine the product(s) of each reaction step.

Using curved arrows, show the mechanism of the following reaction:

Draw structures for the following:

a. (2E,4E)-1-chloro-3-methyl-2,4-hexadiene

b. (3Z,5E)-4-methyl-3,5-nonadiene

c. (3Z,5Z)-4,5-dimethyl-3,5-nonadiene

d. (3E,5E)-2,5-dibromo-3,5-octadiene

Question: a. Which of the monosubstituted cyclohexanes in Table 3.9 on p. 128 has a negative 鈭咷掳 for the conversion of an axial-substituted chair conformer to an equatorial-substituted chair conformer?

b.Which monosubstituted cyclohexane has the most negative 鈭咷掳 for this conversion?

c. Which monosubstituted cyclohexane has the greatest preference for an equatorial position?

d. Calculate 鈭咷掳 for the conversion of 鈥渁xial鈥 methylcyclohexane to 鈥渆quatorial鈥 methylcyclohexane at 25 掳C.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.