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Question: When ethene is mixed with hydrogen in the presence of a platinum catalyst, hydrogen adds across the double bond to form ethane. At room temperature, the reaction goes to completion. Predict the signs ∆H0and∆S0for this reaction. Explain these signs in terms of bonding and freedom of motion.

Short Answer

Expert verified

Answer

The value ∆H0of is negative.

The value of ∆S0is negative.

Step by step solution

01

Enthalpy

The change in enthalpy∆H0 is the heat ofthereaction,which may be defined as the amount of heat evolved or consumed in the course of a reaction. ∆H0is usually given in or . Forming a bond is always exothermic (negative value of∆H0 ) and releases energy,whereas breaking a bond is always endothermic (positive value of ∆H0) and absorbs energy.

02

Entropy

Entropy may be defined as a measure of randomness, disorder, or freedom of motion. Two smaller molecules (or fragments, such as radicals) have more freedom of motion (greater entropy) than one larger molecule.

03

Explanation

Two molecules (ethene and ) have more freedom of motion than a single ethane molecule. Therefore, the change in entropy∆S0 is negative, and the entropy term is positive-T∆S0.

Again, in this reaction, one Ï€C=Cbond and oneÏ€±á=H bond break, while two strong bonds are formedσC-H. This implies that∆H0 has a negative value.

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