Chapter 4: Q 44P (page 234)
Write a mechanism for light-initiated reaction of cyclobutene with chlorine to give chlorocyclobutane. Label the initiation and propagation steps.

Short Answer

Mechanism for free-radical chlorination of cyclobutane
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Chapter 4: Q 44P (page 234)
Write a mechanism for light-initiated reaction of cyclobutene with chlorine to give chlorocyclobutane. Label the initiation and propagation steps.


Mechanism for free-radical chlorination of cyclobutane
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In the presence of a small amount of bromine, cyclohexene undergoes the following light-promoted reaction:

(a) Propose a mechanism for this reaction.
(b) Draw the structure of the rate-limiting transition state.
(c) Use Hammond’s postulate to predict which intermediate most closely resembles this transition state.
(d) Explain why cyclohexene reacts with bromine much faster than cyclohexane, which must be heated to react.
Question: Draw Lewis structures for the following free radicals.
(a)The ethyl radical, CH3-CH2
(b)The tert butyl radical, (CH3 )3C
(c)The isopropyl radical,(2-propyl radical)
(d)The iodine atom
Use bond-dissociation enthalpies (Table 4-2, p.203) to calculate values ofΔHfor the following reactions.
(a)

(b)

(c)

(d)

(e)

(a) Compute the heats of reaction for abstraction of a primary hydrogen and a secondary hydrogen from propane by a fluorine radical.

(b) How selective do you expect free-radical fluorination to be?
(c) What product distribution you expect to obtain from the free-radical fluorination of propane?
(a) Draw the structure of the transition state for the second propagation step in the chlorination of methane.

Show whether the transition state is product-like or reactant-like and which of the two partial bonds is stronger.
(b) Repeat for the second propagation step in the bromination of methane.
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