/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q51P The compound shown below has thr... [FREE SOLUTION] | 91影视

91影视

The compound shown below has three different types of OH groups, all with different acidities. Show the structure produced after this compound is treated with different amounts of NaH followed by a methylating reagent. Add a brief explanation.

(a)1 equivalent of NaH, followed by 1 equivalent of CH3l and heat

(b)2 equivalents of NaH, followed by 2 equivalents of CH3l and heat

(c) 3 equivalents of NaH, followed by 3 equivalents of CH3l and heat

Short Answer

Expert verified

The compounds that are used to synthesize the methyl-substituted organic compound are called methylating agents. Some of the examples are diazomethane, iodomethane, dimethyl sulfate, etc,

Step by step solution

01

About methylating agents

The compounds that are used to synthesize the methyl-substituted organic compound are called methylating agents. Some of the examples are diazomethane, iodomethane, dimethyl sulfate, etc,

02

About sodium hydride

The combustible base that is used in the synthesis of organic compounds is sodium hydride (NaH). This compound is comprised of sodium ions and one proton in a 1:1 ratio.

03

(a) Reaction of the given compound with 1 equivalent of NaH, followed by 1 equivalent CH3l of and heat

The COOH group of the given compound gets converted to group in this reaction. It is shown below.

Reaction of the given compound with 1 equivalent of NaH, followed by 1 equivalent of CH3l and heat

04

(b) Reaction of the given compound with 2 equivalent of NaH, followed by 2 equivalent of CH3l and heat

The COOH group of the given compound gets converted to COOCH3 and one OH group gets converted to OCH3group in this reaction. It is shown below.

Reaction of the given compound with 2 equivalent of NaH, followed by 2 equivalent of CH3l and heat

05

(c) Reaction of the given compound with 3 equivalent of NaH, followed by 3 equivalent of CH3l and heat

The COOH group of the given compound gets converted to COOCH3and two OH group gets converted to OCH3group in this reaction. It is shown below.

Reaction of the given compound with 3 equivalent of NaH, followed by 3 equivalent of CH3l and heat

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Show how you would synthesize the following compound. As starting materials, you may use any alcohols containing five or fewer carbon atoms and any necessary solvents and inorganic reagents.

Under acid catalysis, tetrahydrofurfuryl alcohol reacts to give surprisingly good yields of dihydropyran. Propose a mechanism to explain this useful synthesis.

Trichloroisocyanuric acid, TCICA, also known as 鈥渟wimming pool chlorine,鈥 is a stable solid that oxidizes alcohols, following a mechanism similar to oxidation by HOCl. No reaction occurs between TCICA and the alcohol (in a solvent such as acetonitrile) until one drop of HCl(aq) is added, whereupon the reaction is over in a few minutes. Write the mechanism for this oxidation that shows the key role of the acid catalyst. Show the oxidation of just one alcohol, not three. (Hint: The carbonyls are the most basic sites on TCICA.)

Give the structures of the products you would expect when each alcohol reacts with

(1) HCl, ZnCl2; (2) HBr; (3) PBr3; (4) P/I2; and (5) SOCl2.

(a) butan-1-ol (b) 2-methylbutan-2-ol

(c) 2,2-dimethylbutan-1-ol (d) cis-3-methylcyclopentanol

Both cis- and trans-2-methylcyclohexanol undergo dehydration in warm sulfuric acid to give 1-methylcyclohexene as the major alkene product. These alcohols can also be converted to alkenes by tosylation usingand pyridine, followed by elimination using KOC(CH3)3as a strong base. Under these basic conditions, the tosylate of cis-2-methylcyclohexanol eliminates to give mostly 1-methylcyclohexene, but the tosylate of trans-2-methylcyclohexanol eliminates to give only 3-methylcyclohexene. Explain how this stereochemical difference in reactants controls a regiochemical difference in the products of the basic elimination, but not in the acid-catalyzed elimination.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.