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Neopentyl alcohol, (CH3)3CCH2OH, reacts with concentrated HBr to give 2-bromo-2-methylbutane, a rearranged product. Propose a mechanism for the formation of this product.

Short Answer

Expert verified

Neopentyl alcohol(CH3)3CCH2OHis a primary alcohol, but the bulky group has hinderedit. The backside attack is not possible, so instead of the SN2 mechanism SN1followedto get the desired rearranged product.

The reaction forms a rearranged stable carbocation from primary carbocation to tertiary carbocation.

Step by step solution

01

Step 1: Rearranged Product

Neopentyl alcohol(CH3)3CCH2OHis a primary alcohol, but the bulky group has hinderedit. The backside attack is not possible, so instead of the SN2 mechanism SN1followedto get the desired rearranged product.

The reaction forms a rearranged stable carbocation from primary carbocation to tertiary carbocation.

02

 Mechanism for the formation of 2-bromo-2-methylbutane

Protonation of Neopentyl alcoholconverts the hydroxy group to a good leaving group.

Water leaves form a primary carbocation rearranged through methyl shift, thus forming a stable tertiary carbocation.

Bromide ion attacks the carbocation to form the product 2-bromo-2-methylbutane

Mechanism showing the formation of 2-bromo-2-methylbutane

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