Chapter 11: Q15P (page 559)
Neopentyl alcohol, (CH3)3CCH2OH, reacts with concentrated HBr to give 2-bromo-2-methylbutane, a rearranged product. Propose a mechanism for the formation of this product.
Short Answer

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Chapter 11: Q15P (page 559)
Neopentyl alcohol, (CH3)3CCH2OH, reacts with concentrated HBr to give 2-bromo-2-methylbutane, a rearranged product. Propose a mechanism for the formation of this product.

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The compound shown below has three different types of OH groups, all with different acidities. Show the structure produced after this compound is treated with different amounts of NaH followed by a methylating reagent. Add a brief explanation.

(a)1 equivalent of NaH, followed by 1 equivalent of CH3l and heat
(b)2 equivalents of NaH, followed by 2 equivalents of CH3l and heat
(c) 3 equivalents of NaH, followed by 3 equivalents of CH3l and heat
Propose a mechanism for the reaction of
(a) 1-methyl cyclohexanol with HBr to form 1- bromo-1-methylcyclohexane.
(b) 2- cyclohexylethanol with HBr to form 1-bromo-2-cyclohexylethane.
Predict the major products of the following reactions.
(a)ethyl tosylate+potassium tert-butoxide
(b) isobutyl tosylate + NaI
(c) (R)-2-hexyl tosylate + NaCN
(d) the tosylate of cyclohexylmethanol +excess NH3
When 1-cyclohexylethanol is treated with concentrated aqueous, the major product is 1-bromo-1-ethylcyclohexane.

(a)Propose a mechanism for this reaction.
(b) How would you convert 1-cyclohexylethanol to (1-bromoethyl)cyclohexane in good yield?

Give the structures of the products you would expect when each alcohol reacts with
(1) HCl, ZnCl2; (2) HBr; (3) PBr3; (4) P/I2; and (5) SOCl2.
(a) butan-1-ol (b) 2-methylbutan-2-ol
(c) 2,2-dimethylbutan-1-ol (d) cis-3-methylcyclopentanol
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