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(a) The reaction of butan-2-ol with concentrated aqueous HBr goes with partial racemization, giving more inversion than retention of configuration. Propose a mechanism that accounts for racemization with excess inversion.

(b)Under the same conditions, an optically active sample of trans-2-bromocyclopentanol reacts with concentrated aqueous HBr to give an optically inactive product, (racemic) trans-1,2-dibromocyclopentane. Propose a mechanism to show how this reaction goes with apparently complete retention of configuration, yet with racemization. (Hint: Draw out the mechanism of the reaction of cyclopentene with in water to give the starting material, trans-2- bromocyclopentanol. Consider how parts of this mechanism might be involved in the reaction with HBr.)

Short Answer

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(a) The alcohol that is made up of a carbon skeleton containing four carbons with OH group at the second carbon is butan-2-ol.This compound is a secondary alcohol.

Step by step solution

01

About butan-2-ol

(a) The alcohol that is made up of a carbon skeleton containing four carbons with OH group at the second carbon is butan-2-ol.This compound is a secondary alcohol.

02

About the reaction

There is a possibility of two mechanisms. One path will give 100% of S configuration. Another path will give 50% of S and 50% of R configurations. The two reactions are SN1 and SN2 reactions.

03

About the mechanism

The water blocks all the incoming bromide ions from giving the products resulting from retention of configuration. The dominant pathway is the backside attack ofSN2 type.

04

About trans-2-bromocyclopentanol

(b) The cyclopentanol ring consisting of bromo group in the second carbon trans to the OH group is trans-2-bromocyclopentanol.The carbon skeleton of this compound bears five carbons in a cyclic ring.

05

About the reaction

The reaction is reverse of the formation of bromohydrin. There will be an attack of hydrogen bromide followed by the removal of water. The rearrangement of symmetric bromonium ion leads to the formation of racemic mixture.

06

About the mechanism

The intermediate product in this reaction is a cyclic bromonium ion. The racemic mixture is of trans-1, 2-dibromocyclopentane. Since there is a participation of Br, it is called neighboring group assistance. The mechanism is shown below.

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Most popular questions from this chapter

Both cis- and trans-2-methylcyclohexanol undergo dehydration in warm sulfuric acid to give 1-methylcyclohexene as the major alkene product. These alcohols can also be converted to alkenes by tosylation usingand pyridine, followed by elimination using KOC(CH3)3as a strong base. Under these basic conditions, the tosylate of cis-2-methylcyclohexanol eliminates to give mostly 1-methylcyclohexene, but the tosylate of trans-2-methylcyclohexanol eliminates to give only 3-methylcyclohexene. Explain how this stereochemical difference in reactants controls a regiochemical difference in the products of the basic elimination, but not in the acid-catalyzed elimination.

Under normal circumstances, tertiary alcohols are not oxidized. However, when the tertiary alcohol is allylic, it can undergo a migration of the double bond (called an allylic shift) and subsequent oxidation of the alcohol. A particularly effective reagent for this reaction is Bobbitt’s reagent, similar to TEMPO used in many oxidations. (M. Shibuya et al., J. Org. Chem., 2008, 73, 4750.)

Show the expected product when each of these 3° allylic alcohols is oxidized by Bobbitt’s reagent.

(a)

(b)

(c)

(d)

Show how you would synthesize the following compounds. As starting materials, you may use any alcohols containing four or fewer carbon atoms, cyclohexanol, and any necessary solvents and inorganic reagents.

Two products are observed in the following reaction.

(a) Suggest a mechanism to explain how these two products are formed.

(b) Your mechanism for part (a) should be different from the usual mechanism of the reaction of SOCl2 with alcohols. Explain why the reaction follows a different mechanism in

this case.

Suggest the most appropriate method for each of the following laboratory syntheses. In each case, suggest both a chromium reagent and a chromium-free reagent

(a) butan - 1 - ol → butanal, CH3CH2CH2CHO

(b) but - 2 - en - 1 - ol → but - 2 - enoic acid, CH3CH = CHCOOH

(c) butan - 2 - ol → butan - 2 - one, CH3COCH2CH3

(d) cyclopentanol → 1 - cyclopentylpropan - 1 - ol (twosteps)

(e) cyclopentyclohexanol → 2 - methylcyclohexanone (several steps)

(f) 1 - methylcyclohexanol → 2 - methylcyclohexanone (several steps)

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