/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q6P. Question:a) Draw D-allose, the C... [FREE SOLUTION] | 91影视

91影视

Question:

a) Draw D-allose, the C3 epimer of glucose.

b) Draw D-talose, the C2 epimer of D-galactose.

c) Draw D-idose, the C3 epimer of D-talose. Now compare your answers with Figure 23-3.

d) Draw the C4 鈥渆pimer鈥 of D-xylose. Notice that this 鈥渆pimer鈥 is actually an L-series sugar, and we have seen its enantiomer. Give the correct name for this L-series sugar.

Short Answer

Expert verified

Answer

(a)

(b)

(c)

(d)

Step by step solution

01

Epimers

Epimers are the compounds which are stereoisomers and differ at only one stereogenic center like the placing the OH group is different from the other. For example, D-glucose and D-galactose are epimers having only one chiral center with different configuration.

02

The structure of D-allose, D-talose and 2-idose and their comparison

(a) Epimers are stereoisomers which differs in configuration at any one stereogenic or chiral center. C3 epimer of glucose means configuration differs at carbon-3 of glucose which gives rise to different stereoisomer that is, D-allose. Position of hydroxyl group in glucose at carbon-3 is at left whereas position of hydroxyl group at carbon-3 of D-allose is at right.

The structure of D-allose


(b) Similarly, D-talose is C2 epimer of D-galactose and differs in configuration at carbon-2. Position of hydroxyl group in D-galactose is at right at carbon-2 whereas in D-talose, it is at left. D-idose is C3 epimer of D-talose and differs in configuration at carbon-3.

The structure of D-talose


(c) Position of hydroxyl group is at left at carbon-3 in D-talose whereas it is at right in D-idose.

The structure of D-idose

03

The C4 epimer of D-xylose

(d) C4 epimer of D-xylose is L-arabinose. Change in configuration at carbon-4 of D-xylose with respect to hydroxyl group changes the sugar series from 鈥淒鈥 to 鈥淟鈥 as the change occurred at bottom chiral center which as per convention, leads to formation of enantiomer. The D/L system names molecules by relating them to glyceraldehyde molecule.

The C4 epimer of D-xylose

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An important protecting group developed specifically for polyhydroxy compounds like nucleosides is the tetraisopropyl-disiloxanyl group, abbreviated TIPDS, that can protect two alcohol groups in a molecule.

(a) The TIPDS group is somewhat hindered around the Siatoms by the isopropyl groups. Which OHis more likely to react first with TIPDS chloride? Show the product with the TIPDS group on one oxygen.

(b) Once the TIPDS group is attached at the first oxygen, it reaches around to the next closest oxygen. Show the final product with two oxygens protected.

(c) The unprotected hydroxy group can now undergo reactions without affecting the protected oxygens. Show the product after the protected nucleoside from (b) is treated with tosyl chloride and pyridine, followed by NaBr, ending with deprotection with Bu4NF.

Draw and name the enantiomers of the sugars shown in Figure 23-2. Give the relative configuration (D or L) and the sign of the rotation in each case.

Treatment of either anomer of fructose with excess ethanol in the presence of a trace of HCI gives a mixture of the 伪 and 尾 anomers of ethyl-D-fructofuranoside. Draw the starting materials, reagents, and products for this reaction. Circle the aglycone in each product.

After a series of Kiliani鈥揊ischer syntheses on (+)-glyceraldehyde, an unknown sugar is isolated from the reaction mixture. The following experimental information is obtained:

(1) Molecular formula C6H12O6

(2) Undergoes mutarotation.

(3) Reacts with bromine water to give an aldonic acid.

(4) Reacts with HNO3 to give an optically active aldaric acid.

(5) Ruff degradation followed by HNO3 oxidation gives an optically inactive aldaric acid. (6) Two Ruff degradations followed by HNO3 oxidation give meso-tartaric acid.

(7) When the original sugar is treated with CH3I and Ag2O, a pentamethyl derivative is formed. Hydrolysis gives a tetramethyl derivative with a free hydroxy group on C5.

(a) Draw a Fischer projection for the open-chain form of this unknown sugar. Use Figure 23-3 to name the sugar.

(b) Draw the most stable conform

Question: Propose a mechanism for methylation of any one of the hydroxy groups of methyl--D-glucopyranoside,using and dimethyl sulfate.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.