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H. G. Khorana won the Nobel Prize in Medicine in 1968 for developing the synthesis of DNA and RNA and for helping to unravel the genetic code. Part of the chemistry he developed was the use of selective protecting groups for the 5鈥 OH group of nucleosides.

The trityl ether derivative of just the 5鈥 OH group is obtained by reaction of the nucleoside with trityl chloride, MMT chloride, or DMT chloride and a base like Et3N. The trityl ether derivative can be removed in dilute aqueous acid. DMT derivatives hydrolyze fastest, followed by MMT derivatives, and trityl derivatives slowest.

(a) Draw the product with the trityl derivative on the 5鈥 oxygen.

(b) Explain why the trityl derivative is selective for the 5鈥 OH group. Why doesn鈥檛 it react at 2鈥 or 3鈥? (c) Why is the DMT group easiest to remove under dilute acid conditions? Why does the solution instantly turn orange when acid is added to a DMT derivative?

Short Answer

Expert verified

(a)

(b)

Trityl groups are specific for primary alcohols than secondary or tertiary alcohol, this is due to fact that size of trityl group is more, and secondary or tertiary alcohol will also create steric hindrance. Thus, trityl group is selective for 5鈥 OH group.

(c)

DMT group gets stabilised under acidic conditions, thus gets easily removed. The orange color arises from the extended conjugation through all three rings and out onto methoxy groups in DMT under acidic conditions.

Step by step solution

01

Step-1(a). Trityl derivative product on 5’ oxygen of nucleoside:

Trityl chloride on reaction with nucleoside and in presence of base such as triethylamine, gives the product or trityl derivative which is linked to the 5鈥 oxygen of the nucleoside. This derivative can be easily removed under dilute acidic conditions.

Trityl derivative product

02

Step-2(b). Selectivity of trityl derivative:

Trityl groups are specific for primary alcohols rather than secondary or tertiary alcohols. This is due to steric reasons, as trityl group itself is large and we know that secondary or tertiary alcohols also has some steric hindrance, thus, approach of secondary alcohol is restricted onto trityl derivative and reaction is very slow whereas with primary alcohol, reaction is fast. Thus, trityl group is selective for 5鈥 OH group and not for 2鈥 or 3鈥 group.

03

Step-3(c). Reaction of DMT group under dilute acidic conditions:

DMT group gets stabilised under dilute acid conditions due to extended resonance. Also each methoxy group stabilises the carbocation formed by resonance as depicted in resonating structures. The orange color arises from the extended conjugation which occurs in the DMT group as a result of stabilisation in acidic conditions.

Resonance in DMT group in dilute acidic condition

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Most popular questions from this chapter

Draw and name the enantiomers of the sugars shown in Figure 23-2. Give the relative configuration (D or L) and the sign of the rotation in each case.

a) Draw D-allose, the C3 epimer of glucose.

b) Draw D-talose, the C2 epimer of D-galactose.

c) Draw D-idose, the C3 epimer of D-talose. Now compare your answers with Figure 23-3.

d) Draw the C4 鈥渆pimer鈥 of D-xylose. Notice that this 鈥渆pimer鈥 is actually an L-series sugar, and we have seen its enantiomer. Give the correct name for this L-series sugar.

Draw the expected product of the reaction of the following sugars with excess methyl iodide and silver oxide.

  1. 伪-顿-蹿谤耻肠迟辞蹿耻谤补苍辞蝉别
  2. 尾-顿-驳补濒补肠迟辞辫测谤补苍辞蝉别

The relative configurations of the stereoisomers of tartaric acid were established by the following synthesis:

(1) D-(+)-glyceraldehydediastereomers A and B (separated)

(2) Hydrolysis of A and B using aqueous Ba(OH)2 gave C and D, respectively.

(3) HNO3 oxidation of C and D gave (-)-tartaric acid and meso-tartaric acid, respectively.

(a) You know the absolute configuration of D-(+)-glyceraldehyde, Use Fischer projections to show the absolute configurations of products A, B, C, and D.

(b) Show the absolute configurations of the three stereoisomers of tartaric acid: (+)-tartaric acid, (-)-tartaric acid, and meso-tartaric acid.

Erwin Chargaff鈥檚 discovery that DNA contains equimolar amounts of guanine and cytosine and also equimolar amounts of adenine and thymine has come to be known as Chargaff鈥檚 rule:

G = C and A = T

(a) Does Chargaff鈥檚 rule imply that equal amounts of guanine and adenine are present in DNA? That is, does G = A?

(b) Does Chargaff鈥檚 rule imply that the sum of the purine residues equals the sum of the pyrimidine residues? That is, does A + G = C + T?

(c) Does Chargaff鈥檚 rule apply only to double-stranded DNA, or would it also apply to each individual strand if the double helical strand were separated into its two complementary strands?

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