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Chapter 18: 37 P (page 721)

Draw the products formed when each compound is treated withCH3CH2COCl,AlCl3

Short Answer

Expert verified

a. No reaction

b. No reaction

c.

Step by step solution

01

Friedel-Craft acylation reaction

Treatment of substituted benzene with RCOCl in the presence of the aluminum trichloride results in substitution in the aromatic ring.

02

Product formation in a, b, and c

a. 2-Methyl-1-phenylpropan-1-one does not react with CH3CH2COCl,AlCl3 .

b. N, N-Dimethylaniline does not react with CH3CH2COCl,AlCl3 .

c. The reaction of N-phenylacetamide withCH3CH2COCl,AlCl3 is shown below.

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Most popular questions from this chapter

In Step [2] of Mechanism 18.1, loss of a proton to form the substitution product was drawn using one resonance structure only. Use curved arrows to show how the other two resonance structures can be converted to the substitution product (PhE) by removal of a proton with: B.

Draw a detailed mechanism for the chlorination of benzene using Cl2andFeCl3 .

Question: Draw a stepwise mechanism for the following substitution. Explain why 2-chloropyridine reacts faster than chlorobenzene in this type of reaction.

Draw the products formed when A and B are treated with each of the following reagents:

(a)Br2,FeBr3; (b)HNO3,H2SO4l3; (c) CH3CH2COCl, AlCl3

Question: Using resonance structures, explain why a nitroso group (-NO) is an ortho, para director that deactivates a benzene ring toward electrophilic attack.
See all solutions

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