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Question: When a molecule can form two different structures, the structure with the stronger bonds is usually the more stable form. Use bond energies to predict the correct structure of the hydroxylamine molecule:

Short Answer

Expert verified

Since bond energy of left molecule is \({\rm{B}}{\rm{.E}}{\rm{. = 1444\;kJ}}\), which is more than the bond energy of right molecule i.e., \({\rm{B}}{\rm{.E}}{\rm{. = 1370\;kJ}}\) therefore, left molecule is more stable and is the correct structure.

Step by step solution

01

Concept Introduction

Bond energy, also known as mean bond enthalpy or average bond enthalpy in chemistry, is a measure of the bond strength in a chemical bond.

02

Bond Energy for Hydroxylamine

Observe the structure –

Bond Energy for\({\rm{N - H}}\)is:\({\rm{390 kJ/mol}}\)

Bond Energy for\({\rm{N - O}}\)is:\({\rm{200 kJ/mol}}\)

Bond Energy for\({\rm{O - H}}\)is:\({\rm{464 kJ/mol}}\)

Calculate the bond energy –

\(\begin{array}{l}{\rm{B}}{\rm{.E}}{\rm{. = 2(390) + 200 + 464}}\\{\rm{B}}{\rm{.E}}{\rm{. = 1444 kJ}}\end{array}\)

Therefore, the bond energy is \({\rm{B}}{\rm{.E}}{\rm{. = 1444\;kJ}}\).

03

Bond Energy for Hydroxylamine

Observe the structure –

Bond Energy for \({\rm{N - H}}\) is: \({\rm{390 kJ/mol}}\)

Bond Energy for \({\rm{N - O}}\) is: \({\rm{200 kJ/mol}}\)

Calculate the bond energy –

\(\begin{array}{l}{\rm{B}}{\rm{.E}}{\rm{. = 3(390) + 200}}\\{\rm{B}}{\rm{.E}}{\rm{. = 1370 kJ}}\end{array}\)

Therefore, the bond energy is \({\rm{B}}{\rm{.E}}{\rm{. = 1370\;kJ}}\).

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In the Lewis structures listed here, M and X represent various elements in the third period of the periodic table. Write the formula of each compound using the chemical symbols of each element:

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