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Use the simulation (http://openstaxcollege.org/l/16MolecPolarity) to perform the following exercises for a real molecule. You may need to rotate the molecules in three dimensions to see certain dipoles. (a) Sketch the bond dipoles and molecular dipole (if any) for O3. Explain your observations. (b) Look at the bond dipoles for NH3. Use these dipoles to predict whether N or H is more electronegative. (c) Predict whether there should be a molecular dipole for NH3 and, if so, in which direction it will point. Check the molecular dipole box to test your hypothesis.

Short Answer

Expert verified

a) CentralOatom, has partial positive charge

Other twoOatoms have partial negative charge (and are equally charged)

Since molecule is bent, bond moments will not cancel each other. The molecule dipole is equal to the vector sum of bond moments, and the molecule is polar.

b)All bond dipoles are pointed at\(N\)atom, hence, the Electronegativity of\({\rm{N}}\)is higher than the Electronegativity of\({\rm{H}}\)

c) The direction of a molecular dipole for \({\rm{N}}{{\rm{H}}_3}\) is shown on the sketch.

Step by step solution

01

Definition of dipole

A dipole usually refers to the separation of charges within a molecule between two covalently bonded atoms or atoms that share an ionic bond

02

Sketch the bond dipoles and molecular dipole (if any) for O3

a)

For\({{\rm{O}}_3}\), we must draw the bond dipoles and molecular dipoles.

Bond moments will not cancel each other since the molecule is bent. The vector total of bond moments equals the molecule dipole, and the molecule is polar.

Therefore,partially positive charge on the central atom.

The other two atoms are somewhat charged negatively (and are equally charged)

Bond moments do not cancel each other since the molecule is bent. The vector total of bond moments equals the molecule's dipole, and the molecule is polar.

03

dipoles to predict whether N or H is more electronegative

b)

Explanation,

- TheOatom in the center has a partial positive charge.

- The other twoOatoms are somewhat charged (and are equally charged)

Bond moments will not cancel each other since the molecule is bent. The vector total of bond moments equals the molecule dipole, and the molecule is polar.

Therefore,because all bond dipoles point toward the\(N\)atom, the Electronegativity of is\({\rm{H}}\)greater than the Electronegativity of\(N\).

04

Step 4: Check the molecular dipole box

c) For\({\rm{N}}{{\rm{H}}_3}\), we must now anticipate the direction of a molecule dipole.
The molecular dipole will be pointed as depicted in the sketch since it has a trigonal pyramid structure and all three bond dipoles are pointing towards N Atom.

Therefore, on the sketch, the direction of a molecule dipole is \({\rm{N}}{{\rm{H}}_3}\) depicted.

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Most popular questions from this chapter

Which of the following molecules have dipole moments?

  1. \({\rm{C}}{{\rm{S}}_{\rm{2}}}\)
  2. \({\rm{Se}}{{\rm{S}}_{\rm{2}}}\)
  3. \({\rm{CC}}{{\rm{l}}_{\rm{2}}}{\rm{\;}}{{\rm{F}}_{\rm{2}}}\)
  4. \({\rm{PC}}{{\rm{l}}_{\rm{3}}}{\rm{(P is the central atom)}}\)
  5. \({\rm{ClNO (N is the central atom)}}\)

Write resonance forms describing the distribution of electrons in each molecule or ion.

a) selenium dioxide, \({\rm{OSeO}}\)

(b) nitrate ion, \({\rm{NO}}_{\rm{3}}^{\rm{ - }}\)

(c) nitric acid, \({\rm{HN}}{{\rm{O}}_{\rm{3}}}\) (\({\rm{N}}\) is bonded to an \({\rm{OH}}\) group and two \({\rm{O}}\) atoms)

(d) benzene, \({{\rm{C}}_{\rm{6}}}{{\rm{H}}_{\rm{6}}}\):

(e) the formate ion:

Describe the molecular structure around the indicated atom or atoms:

  1. The sulfur atom in sulfuric acid, H2SO4 [ (HO)2 SO2]

  2. The chlorine atom in chloric acid, HClO3 [HOClO2]

  3. The oxygen atom in Hydrogen peroxide, HOOH

  4. The nitrogen atom in nitric acid, HNO3 [HONO2]

  5. The oxygen atom in OH group in nitric acid, HNO3 [HONO2]

  6. The central oxygen atom in the ozone molecule, O3

  7. Each of the carbon atoms in the propyne, CH3 CCH

  8. The carbon atom in Freon, CCl2 F2

  9. each of the carbon atoms in allene H2CCCH2

Write out the full electron configuration for each of the following atoms and for the monatomic ion found in binary ionic compounds containing the element: (a) \({\rm{Al}}\) (b) \({\rm{Br}}\) (c) \({\rm{Sr}}\) (d) \({\rm{Li}}\) (e) \({\rm{As}}\) (f) \({\rm{S}}\) .

Use the Molecule Shape simulator (http://openstaxcollege.org/l/16MolecShape) to build a molecule. Starting with the central atom, click on the double bond to add one double bond. Then add one single bond and one lone pair. Rotate the molecule to observe the complete geometry. Name the electron group geometry and molecular structure and predict the bond angle. Then click the check boxes at the bottom and right of the simulator to check your answers.

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