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Calculate the pH of a 200 mL solution of pure water to which has been added 50 mL of 1 mM HCl.

Short Answer

Expert verified

The pH value of total solution is 3.7.

Step by step solution

01

Concentration of H+ ions in the total solution

Total amount of solution=250 mL

Pure water has a pH of 7. So, its hydrogen ion concentration is:

[H+]=10-7M

Here,H+ is hydrogen ion concentration.

The added 50 ml of solution had H+ concentration of 1x10-3 M (1mM HCl).

Thus, total concentration of H+ in the solution is calculated as:.

[H+]= (50mLx1mM)/250mL

[H+]=(0.05L×0.001M)0.25L+10-7M=(2×10-4+10-7)M=2×10-4M.

02

Calculation of pH

pH=log[H+]Now,[H]+=2×10-4MpH=-log(2×10-4M)=3.7

Therefore, the pH value of the total solution is 3.7.

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