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You wish to sequence the light chain of a protease inhibitor from the Brassica nigra plant. Cleavage of the light chain by trypsin and chymotrypsin yields the following fragments. What is the sequence of the light chain?

Chymotrypsin

1. Leu–His–Lys–Gln–Ala–Asn–Gln–Ser–Gly–Gly–Gly–Pro–Ser

2. Gln–Gln–Ala–Gln–His–Leu–Arg–Ala–Cys–Gln–Gln–Trp

3. Arg–Ile–Pro–Lys–Cys–Arg–Lys–Phe

Trypsin

4. Arg

5. Ala–Cys–Gln–Gln–Trp–Leu–His–Lys

6. Cys–Arg

7. Gln–Ala–Asn–Gln–Ser–Gly–Gly–Gly–Pro–Ser

8. Phe–Gln–Gln–Ala–Gln–His–Leu–Arg

9. Ile–Pro–Lys

10. Lys

Short Answer

Expert verified

The light chain will have the sequence:

Arg – Ile – Pro – Lys – Cys – Arg – Lys – Phe – Gln – Gln – Ala – Gln – His – Leu – Arg – Ala – Cys – Gln – Gln – Trp Leu – His – Lys – Gln – Ala – Asn – Gln – Ser – Gly – Gly – Gly – Pro – Ser.

Step by step solution

01

Protein Sequencing

The sequence of a protein is determined by breaking the intact polypeptide into smaller fragments of amino acids. This process is repeated twice using 2 different endopeptidases—enzymes that break the peptide bond present between the amino acids, to produce 2 different sets of fragments of the same polypeptide. These fragments are sequenced and then overlapped to determine the whole sequence of the polypeptide.

02

Cleavage by Trypsin and Chymotrypsin

Trypsin and Chymotrypsin are endopeptidases which are isolated from Bovine pancreas. Only when the next amino acid residue is not Proline (Pro), Trypsin breaks the peptide bond on the C side (carboxyl terminus) of positively charged amino acids Lysine (Lys), and Arginine (Arg).

Only when the next residue is not Proline, Chymotrypsin cleaves peptide bonds on the C side (carboxyl terminus) of bulky hydrophobic residues which are Tyrosine (Tyr), Phenylalanine (Phe), and Tryptophan (Trp).

03

Explanation

When the fragments obtained of light chain of protease inhibitor treated with trypsin and chymotrypsin are overlapped, they give the whole sequence of the light chain.

Thus, the sequence of the protease inhibitors light chain is

Arg – Ile – Pro – Lys – Cys – Arg – Lys – Phe – Gln – Gln – Ala – Gln – His – Leu – Arg – Ala – Cys – Gln – Gln – Trp Leu – His – Lys – Gln – Ala – Asn – Gln – Ser – Gly – Gly – Gly – Pro – Ser.

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Most popular questions from this chapter

Question: Purification tables are often used to keep track of the yield and purification of a protein. The specific activity is a ratio of the amount of the protein of interest, in this case Mb, obtained at a given step (μmol or enzyme units) divided by the amount (mg) of total protein. The yield is the ratio of the amount of the protein of interest obtained at a given step (μmol or enzyme units) divided by the original amount present in the crude extract, often converted to percent yield by multiplying by 100. The fold purification is the ratio of the specific activity of the purified protein to that of the crude preparation.

(a) For the purification table below, calculate the specific activity, % yield, and fold purification for the empty cells.

(b) Which step—DEAE or affinity chromatography—causes the greatest loss of Mb?

(c) Which step causes the greater purification of Mb?

(d) If you wanted to use only one purification step, which technique would you choose?

Treatment of a polypeptide with 2-mercaptoethanol yields two polypeptides:

1. Ala–Val–Cys–Arg–Thr–Gly–Cys–Lys–Asn–Phe–Leu

2. Tyr–Lys–Cys–Phe–Arg–His–Thr–Lys–Cys–Ser

Treatment of the intact polypeptide with trypsin yields fragments with the following amino acid compositions:

3. (Ala, Arg, Cys2, Ser, Val)

4. (Arg, Cys2, Gly, Lys, Thr, Phe)

5. (Asn, Leu, Phe)

6. (His, Lys, Thr)

7. (Lys, Tyr)

Indicate the positions of the disulfide bonds in the intact polypeptide.

(a) The ESI-MS spectrum below was obtained for hen egg-white lysozyme (HEWL). Using peaks 5 and 6, calculate the molecular mass of HEWL (see Sample Calculation 5-1).

[http://www.astbury.leeds.ac.uk/facil/MStut/mstutorial.htm. Published by A.E. Ashcroft, Astbury Centre for Structural Molecular Biology, University of Leeds (2000)]

(b) What is the charge on the ion that makes peak 5?

Draw a different phylogenetic tree based on the data in Problem 19.

Separate cleavage reactions of a polypeptide by CNBr and chymotrypsin yield fragments with the following amino acid sequences. What is the sequence of the intact polypeptide?

CNBr treatment

1. Arg–Ala–Tyr–Gly–Asn

2. Leu–Phe–Met

3. Asp–Met

Chymotrypsin

4. Met–Arg–Ala–Tyr

5. Asp–Met–Leu–Phe

6. Gly–Asn

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