/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q26P Calculate the magnitude of the f... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 6: Q26P (page 1249)

Calculate the magnitude of the force required to give a 0.145-kg baseball an acceleration a = 1.00 m/s^2 in the direction of the baseball鈥檚 initial velocity when this velocity has a magnitude of (a) 10.0 m/s; (b) 0.900c; (c) 0.990c. (d) Repeat parts (a), (b), and (c) if the force and acceleration are perpendicular to the velocity.

Short Answer

Expert verified

The magnitude of forces when the force and the acceleration are along the same line to the velocity..

a)F=0.145N

b)F=1.75N

c)F=51.7N

d)Where the force and the acceleration are perpendicular to the velocity.

a) F=0.145N

b) F=0.333N

c) F=1.03N

Step by step solution

01

Step 1:Formula of magnitude of the force.

When force and acceleration in same line,

F=纬3ma

When force and acceleration are perpendicular.

F=纬ma

In both the cases,

纬=11-u2c2

02

Step 2:Calculating the force of magnitude when along the same line.

a)

F=11-1023脳10820.145*1=0.145N

b)

F=11-0.900c2c20.145*1=1.75N

c)

F=11-0.990c2c20.145*1=51.7N

03

Calculating the force of magnitude when perpendicular to each other.

d)

a) F=11-1023脳10820.145*1=0.145N

b)F=11-0.900c2c20.145*1=0.333N

c)F=11-0.990c2c20.145*1=1.03N

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Why Are We Bombarded by Muons? Muons are unstable subatomic particles that decay to electrons with a mean lifetime of 2.2渭s. They are produced when cosmic rays bombard the upper atmosphere about km above the earth's surface, and they travel very close to the speed of light. The problem we want to address is why we see any of them at the earth's surface. (a) What is the greatest distance a muon could travel during its 2.2渭蝉lifetime? (b) According to your answer in part (a), it would seem that muons could never make it to the ground. But the 2.2-碌s lifetime is measured in the frame of the muon, and muons are moving very fast. At a speed of 0.999c, what is the mean lifetime of a muon as measured by an observer at rest on the earth? How far would the muon travel in this time? Does this result explain why we find muons in cosmic rays? (c) From the point of view of the muon, it still lives for only 2.2渭s, so how does it make it to the ground? What is the thickness of the 10 km of atmosphere through which the muon must travel, as measured by the muon? Is it now clear how the muon is able to reach the ground?

The black dots at the top of Fig. represent a series of high-speed photographs of an insect flying in a straight line from left to right (in the positive x-direction). Which of the graphs in Fig. most plausibly depicts this insect鈥檚 motion?

Why must engineers and scientists shield against x-ray production in high-voltage equipment?

Inside a spaceship flying past the earth at three-fourths the speed of light, a pendulum is swinging. (a) If each swing takes 1.80 s as measured by an astronaut performing an experiment inside the spaceship, how long will the swing take as measured by a person at mission control (on earth) who is watching the experiment? (b) If each swing takes 1.80 s as measured by a person at mission control, how long will it take as measured by the astronaut in the spaceship?

Human skin is relatively insensitive to visible light, but ultraviolet radiation can cause severe burns. Does this have anything to do with photon energies? Explain.
See all solutions

Recommended explanations on Physics Textbooks

Fluids

Read Explanation

Rotational Dynamics

Read Explanation

Solid State Physics

Read Explanation

Oscillations

Read Explanation

Thermodynamics

Read Explanation

Work Energy and Power

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.